Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
493 comments Page 27 of 50.
Givid said:
1 decade ago
I have a doubt on question. Whose speed is 5km/hr? either the man's or train's? please explain.
Santhosh K said:
2 years ago
@All.
Why do we minus the speed of the man moving in the same direction? Please explain to me.
Why do we minus the speed of the man moving in the same direction? Please explain to me.
(39)
Ananya said:
9 years ago
How can the answer be 50 that's the point x-5 would be 40 kmph?
Then how can b be the answer?
Then how can b be the answer?
M.kanna said:
1 decade ago
18/5 explanation is super k/m h/r put 1000/3600=5/18 answer is very nice apserve then nice.
Mathivanan said:
1 decade ago
Can anyone explain how to find length of train when the train speed and person speed given?
Swamy chukkala said:
1 decade ago
Well,
10 sec ----125 mt.
36 sec----- = (36/10)*125 = 450 mt = 450/10 = 45 + 5 = 50 km/hr.
10 sec ----125 mt.
36 sec----- = (36/10)*125 = 450 mt = 450/10 = 45 + 5 = 50 km/hr.
Nish said:
1 decade ago
When we convert km/h to m/sec in that situation we multiple 5/18 and same opposition 18/5.
Narendra said:
8 years ago
In same direction, T. S-M. S = 125/10 * 18/5 = 45.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.
Luci said:
6 years ago
We are finding the speed of the train.
So,
Speed = distance /time.
=> Speed = 125/10.
So,
Speed = distance /time.
=> Speed = 125/10.
AAKASH said:
1 decade ago
125m/10s*18/5=45.
The man running in opposite direction at a speed of 5 km so 45+5=50.
The man running in opposite direction at a speed of 5 km so 45+5=50.
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