Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
475 comments Page 27 of 48.
Mathivanan said:
1 decade ago
Can anyone explain how to find length of train when the train speed and person speed given?
Swamy chukkala said:
10 years ago
Well,
10 sec ----125 mt.
36 sec----- = (36/10)*125 = 450 mt = 450/10 = 45 + 5 = 50 km/hr.
10 sec ----125 mt.
36 sec----- = (36/10)*125 = 450 mt = 450/10 = 45 + 5 = 50 km/hr.
Nish said:
1 decade ago
When we convert km/h to m/sec in that situation we multiple 5/18 and same opposition 18/5.
Narendra said:
7 years ago
In same direction, T. S-M. S = 125/10 * 18/5 = 45.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.
Luci said:
5 years ago
We are finding the speed of the train.
So,
Speed = distance /time.
=> Speed = 125/10.
So,
Speed = distance /time.
=> Speed = 125/10.
AAKASH said:
1 decade ago
125m/10s*18/5=45.
The man running in opposite direction at a speed of 5 km so 45+5=50.
The man running in opposite direction at a speed of 5 km so 45+5=50.
Jeevitha said:
8 years ago
Here 18/5 used. Because to convert 125m to km/hr from km/hr to m/sec multiply by 5/18.
Jayan said:
1 decade ago
Here x=45 is speed of per 1km. question is 5km/hr .
So
x-5=45
x=45+5
x=50
Thats all.
So
x-5=45
x=45+5
x=50
Thats all.
Ganesh said:
7 years ago
They asked the train speed; but why we have to take relative speed?
Please tell me.
Please tell me.
Saranya said:
1 decade ago
I could not understand this problem is there any way to understand this more easily.
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