Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 27 of 48.

Mathivanan said:   1 decade ago
Can anyone explain how to find length of train when the train speed and person speed given?

Swamy chukkala said:   10 years ago
Well,

10 sec ----125 mt.

36 sec----- = (36/10)*125 = 450 mt = 450/10 = 45 + 5 = 50 km/hr.

Nish said:   1 decade ago
When we convert km/h to m/sec in that situation we multiple 5/18 and same opposition 18/5.

Narendra said:   7 years ago
In same direction, T. S-M. S = 125/10 * 18/5 = 45.
M.S = 5KMph.
T.S - 5 = 45.
T.S = 50sec.

Luci said:   5 years ago
We are finding the speed of the train.
So,
Speed = distance /time.
=> Speed = 125/10.

AAKASH said:   1 decade ago
125m/10s*18/5=45.

The man running in opposite direction at a speed of 5 km so 45+5=50.

Jeevitha said:   8 years ago
Here 18/5 used. Because to convert 125m to km/hr from km/hr to m/sec multiply by 5/18.

Jayan said:   1 decade ago
Here x=45 is speed of per 1km. question is 5km/hr .
So
x-5=45
x=45+5
x=50
Thats all.

Ganesh said:   7 years ago
They asked the train speed; but why we have to take relative speed?

Please tell me.

Saranya said:   1 decade ago
I could not understand this problem is there any way to understand this more easily.


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