Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
475 comments Page 30 of 48.
Pradeep said:
1 decade ago
From The Question 5Km/hr So please explain it 1000/3600. give me reason.
David said:
9 years ago
@Jaydev Ramnath
To convert km/hr into m/s we should multiply with 18/5.
To convert km/hr into m/s we should multiply with 18/5.
Abhishek said:
1 decade ago
Can anyone find another way of solving this? Apart from relative speed?
Meera said:
1 decade ago
Thanks mr. Suganthan. Its really very nice to understand thanks:) ) ).
Nagaraj said:
1 decade ago
It should be taken as 1000/60*60 beacuse distance covered/ time taken.
Jeevanantham said:
1 decade ago
How to relative 45 with man running speed. Please explain it any one.
Nivetha said:
8 years ago
What is the meaning of (x-5) then, x-5=45?
Please explain this line.
Please explain this line.
Raghu said:
1 decade ago
How it is 3600/1000. It will come as 1000/3600 only. Please explain.
NIRMAL said:
1 decade ago
Vijay Kumar Kuppani you did solve problem very nicely again thanks.
Ramkumar said:
1 decade ago
Why use 60*60/1000(18/5) I do not understand that?
Please explain.
Please explain.
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