Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 29 of 48.

Hunt said:   1 decade ago
Relative velocity of train with respect to a fixed point (Let assume a pole).

v = u-5 [u is the velocity of train & 5 is of man & in same direction so negative sign].

Now by simple equation.

Length = Speed x Time.

125 = (u-5*5/18)10.

So u = 250/18 m/s = 50 km/h.

Sushma said:   1 decade ago
Why should we use x-5 here please explain once again.

Raja said:   1 decade ago
18/5 is to convert m/s to km/hr.

5/18 is to convert km/hr to m/sec.

1 km = 1000 m
1 hr = 3600 s.

M = 1 km/1000
s =1 hr/3600.

M/s = (3600/1000) km/hr.

= (5/18) km/hr.
------------------------------------------------.
Km/hr = (1000/3600) m/s.

= (5/18) m/s.

Vashu said:   1 decade ago
What is 5/18 and where its come in?

Varma said:   1 decade ago
How he equated 45 to x-5?

Ravindra said:   1 decade ago
X-5 = 45 is right because train and man same side. In same side it is correct.

Nikhil said:   1 decade ago
We have added the 5 km/hr to the final answer because the speed that comes out is with respect to man and to calculate the actual speed of the train we have added 5 km/hr to the final answer.

Mohit kumar said:   1 decade ago
1 km = 1000 m/1 hr = 3600 sec = 5/18 but we want to convert just opposite.

So numerator and denominator will be interchange.

Prammeela.t said:   1 decade ago
Why we relate the speed of man and train length?

Sravani said:   1 decade ago
Why relative speed? They asked only speed?


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