Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 30 of 48.

Mahinia said:   1 decade ago
Train is same dxn and man is also some dxn it means it means speed is minus x-5 = 125/10*18/5 = 50.

Pranil T. Mhatre said:   1 decade ago
Length of the train = 125 m.
Speed of the man = 5 km/hr.
Speed of the man in meters = (5*1000)/(60*60)=(50/36)=(25/18).
=1.388 m/sec.

Since train has covered the distance in 10 secs.
Let us calculate the distance covered by the man in 10 secs.
distance covered by the man in 10 secs = 13.88 m.

Therefore the displacement(d) = 125 m+13.88 m = 138.88 m.

Speed of the train = (138.88/10) = 13.88 m/s.

Therefore The Speed of the train in Hours = 13.88 * 60 * 60 = 50000 m/sec = 50 Km/hr.

Murugan MJ said:   1 decade ago
@Hemavathy. Since man is moving in same direction with train the relative speed is s-5 so,

s-5 = 45.
s = 50 km/hr.


Suppose if man move in opposite direction of train then,

s+5 = 45.
s = 40 km/hr.

Hemavathy said:   1 decade ago
How the will be 50?
Speed = 25/2(m/s).

Converting(m/s)to(km/hr).
25/2*18/5 = 45.

Jabi Mir said:   1 decade ago
The only thing to remember is that when objects are moving in the same direction,then relative speed is equal to subtraction of their respective speeds and when the objects are moving in opposite direction,then relative speed is equal to addition of their respective speeds.

Therefore, here v1 = 5 km/h, v2=?, t=10sec => 10/3600 hr.,
Distance = 125 mt => 125/1000 kms.

Now we know, Speed=distance/time.
or we can say, Relative speed = distance/time.

Since here relative speed= v2-v1 (objects moving in same direction).
Therefore, v2-5=125/1000 whole divided by 10/3600.

or, v2-5=125/1000 * 3600/10, on solving we get,
v2-5= 45 => v2 = 45+5 => V2=50 Km/hr.

Shibin said:   1 decade ago
Relative speed = x-5 (x is the speed of train).
(x-5)*5/18 = 125/10.
x-5 = 125*18/10*5.
x-5 = 125*9/25.
x-5 = 5*9.
x-5 = 45.
x = 50.

Navi said:   1 decade ago
Hi @Swati look here let me explain:
L = Speed*time.

And,
Speed = length/time.
Length = 25/2.
Time = 5/18.

And,
25/2/5/18 = 25/2*18/5.
9*5 = 45km/hr.
x-5 = 45.

45+5 = x.
x = 50km/hr.

GwenBiz said:   1 decade ago
@Jothi,

x-5 = 45.
We add 5 to both sides so that we stay with x.

x-5+5 = 45+5.
Therefore,

So x = 50.

Muhammed areeb said:   1 decade ago
Why use 60*60/1000(18/5) I do not understand that?

Givid said:   1 decade ago
I have a doubt on question. Whose speed is 5km/hr? either the man's or train's? please explain.


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