Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 10 of 11.
Crack said:
6 years ago
I know why 5/18 is calculate. But in this particular math they didn't mention anything related to meter. Only answer is given in second, so we should only convert hr to seconds right? why we converted the km also? train length and speed both are in km, also in answer there's no km unit, only second. So please explain this part.
Gou said:
6 years ago
How to solve (2000*3÷125) ? please explain in breif.
Madhav Kulkarni said:
6 years ago
Relative Speed in Opposite Direction = 60+50 = 150km/h=150*(5/18)=41.66.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
(2)
Rony said:
5 years ago
Why not solve in km?
Speed & distance should be in km, right?
Speed & distance should be in km, right?
Jinni said:
5 years ago
The time for the long train will be the same right?
(2)
Sathya said:
5 years ago
If the faster train is cross across the slow train?
Then, What is the answer?
Then, What is the answer?
(6)
Shubham said:
4 years ago
@All.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
(36)
Jakath said:
4 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(8)
Jakath said:
4 years ago
U = (1.10+0.9)km/(90+60)km/hr,
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
= 2km/150km/hr,
= 2/150 hr.
= 2/150 = 0.0133hr = 0.0133 * 60 * 60 = 48sec.
(4)
Datta vadare said:
4 years ago
T = length/speed.
T = 2000/3/725,
T = 48 sec.
T = 2000/3/725,
T = 48 sec.
(7)
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