Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
285 comments Page 4 of 29.
Uttam Roy said:
12 months ago
The speed of train = 54 x 5/18m/s,
= 15m/s.
Length of train = 15 x 20 = 300 meters ∴( distance = speed x time),
Total length = 15 x 30 = 540 (length of train x platform time taken to reach out),
The final answer is 540 - 300 meters.
= 240 meters.
= 15m/s.
Length of train = 15 x 20 = 300 meters ∴( distance = speed x time),
Total length = 15 x 30 = 540 (length of train x platform time taken to reach out),
The final answer is 540 - 300 meters.
= 240 meters.
(8)
Avinash said:
2 years ago
Here already taken by speed in 15m/sec.
And train length 15 × 20 = 300 m.
Then why take by the agin 15m/sec× 36 seconds can you explain this?
And train length 15 × 20 = 300 m.
Then why take by the agin 15m/sec× 36 seconds can you explain this?
(7)
Virender Singh said:
5 years ago
Answer 240m is possible only if the man is standing at the end of the station.
Am I right or wrong? Please anyone clarify.
Am I right or wrong? Please anyone clarify.
(6)
Ravi Kumar said:
4 years ago
The length of platform = x + 300/36 = 15 m/s.
Can someone explain why we write the 15 m/s on R.H.S of the equation?
I really could not understand. If someone knows then please help me.
Can someone explain why we write the 15 m/s on R.H.S of the equation?
I really could not understand. If someone knows then please help me.
(5)
Vishnu Kawale said:
11 months ago
Here, the length of the train is very small compared to real life.
(5)
Prathamesh Devrukhakar said:
6 months ago
@Sai.
1 km/hr = 5/18 m/s.
1 km/hr = 5/18 m/s.
(5)
Hemant said:
2 months ago
@All.
First, identify the distance:
> Crossing a man/pole/tree?
Distance = Length of the train.
> Crossing a platform/bridge/tunnel?
Distance = Length of train + Length of platform.
> Crossing another train?
Distance = Length of Train A + Length of Train B.
First, identify the distance:
> Crossing a man/pole/tree?
Distance = Length of the train.
> Crossing a platform/bridge/tunnel?
Distance = Length of train + Length of platform.
> Crossing another train?
Distance = Length of Train A + Length of Train B.
(5)
Rakesh said:
5 years ago
I have solved this problem in a different way, is this the right way to solve it?
Speed=15 m/sec.
Total length of train is 300m,
let length of the plateform be x m,
total distance = speed * time,
x + 300 = 15*36,
x + 300 = 540,
x = 240m.
Speed=15 m/sec.
Total length of train is 300m,
let length of the plateform be x m,
total distance = speed * time,
x + 300 = 15*36,
x + 300 = 540,
x = 240m.
(4)
Kratika said:
5 years ago
Why didn't we added the length of the man? Please explain.
(3)
Rajeshwari said:
3 months ago
Given:
Step1: Convert speed (km/hr)to(m/s) : (54*5/18)=15
Step2: Find the length of the train: speed*time required by the man standing on platform = 15 * 20 = 300 m
Step3: To find the length of the platform:
length of platform = x.
= (x + length of the train) /time required by the train to pass the station platform
15 = x + 300/36,
x + 300 = (15)(36),
x + 300 = 540,
x = 540 - 300,
x = 240m.
Step1: Convert speed (km/hr)to(m/s) : (54*5/18)=15
Step2: Find the length of the train: speed*time required by the man standing on platform = 15 * 20 = 300 m
Step3: To find the length of the platform:
length of platform = x.
= (x + length of the train) /time required by the train to pass the station platform
15 = x + 300/36,
x + 300 = (15)(36),
x + 300 = 540,
x = 540 - 300,
x = 240m.
(3)
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