Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
Speed = | ![]() |
54 x | 5 | ![]() |
18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, | x + 300 | = 15 |
36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 1 of 28.
Vishnu Kawale said:
4 weeks ago
Here, the length of the train is very small compared to real life.
(1)
ESNALA SIDDA said:
4 weeks ago
1) First calculate the train distance.
D = S×T.
S = 54×5/18,
S = 15m/s,
D = 15×20 = 300m.
2) Calculate the platform + train distance.
D = 36×15
= 540m
Platform distance
540 - 300 = 240m.
D = S×T.
S = 54×5/18,
S = 15m/s,
D = 15×20 = 300m.
2) Calculate the platform + train distance.
D = 36×15
= 540m
Platform distance
540 - 300 = 240m.
(12)
Uttam Roy said:
1 month ago
The speed of train = 54 x 5/18m/s,
= 15m/s.
Length of train = 15 x 20 = 300 meters ∴( distance = speed x time),
Total length = 15 x 30 = 540 (length of train x platform time taken to reach out),
The final answer is 540 - 300 meters.
= 240 meters.
= 15m/s.
Length of train = 15 x 20 = 300 meters ∴( distance = speed x time),
Total length = 15 x 30 = 540 (length of train x platform time taken to reach out),
The final answer is 540 - 300 meters.
= 240 meters.
(7)
T S SOUNDHAR said:
4 months ago
Train cross the platform is 36sec.
A man standing (passenger for boards) is = 20 sec,
Total train running time on the platform is = 36 - 20 = 16sec.
So,
54km/hr = 54000/3600 = (540/36) = 15m/s,
platform length = 16 * 15 = 240m is the answer.
A man standing (passenger for boards) is = 20 sec,
Total train running time on the platform is = 36 - 20 = 16sec.
So,
54km/hr = 54000/3600 = (540/36) = 15m/s,
platform length = 16 * 15 = 240m is the answer.
(42)
Aditya said:
4 months ago
540 is the total distance that includes train length+ and platform length.
Here we need only platform length that's why we need train length or you can get another approach like 36-20=16sec. It's the time of starting of the train and the starting of exist platform 15 meters per sec * 16 sec = 240 meters.
Here we need only platform length that's why we need train length or you can get another approach like 36-20=16sec. It's the time of starting of the train and the starting of exist platform 15 meters per sec * 16 sec = 240 meters.
(8)
Sai said:
4 months ago
How 5/18 is came sir?
(6)
Reuben said:
7 months ago
@All.
Here is the explanation:
Train speed is 54 km/h.
(Sum of the seconds taken for cross = 36 - 20 =16 sec.
If we know how many meters crossed in 1 sec we can find how long that travelled in 16 sec)
The train can cross 54 km per 1 hour.
54km =5400m (because we need ans in m)
1 hour = 60mnts and 60 sec total 3600 sec.
Check the unit mentioned km/h.
We have 54000 for km and 3600 for hour.
Substitute this in km/h.
54000/3600 = 540/36 = 180/12.
= 90/6 = 15.
So, the train can cross 15m per sec;
So it takes 1 sec for 15m.
Then it takes 16 sec to cross.
15 * 16 = 240 m.
So, the train crossed 240 m length of the platform.
Here is the explanation:
Train speed is 54 km/h.
(Sum of the seconds taken for cross = 36 - 20 =16 sec.
If we know how many meters crossed in 1 sec we can find how long that travelled in 16 sec)
The train can cross 54 km per 1 hour.
54km =5400m (because we need ans in m)
1 hour = 60mnts and 60 sec total 3600 sec.
Check the unit mentioned km/h.
We have 54000 for km and 3600 for hour.
Substitute this in km/h.
54000/3600 = 540/36 = 180/12.
= 90/6 = 15.
So, the train can cross 15m per sec;
So it takes 1 sec for 15m.
Then it takes 16 sec to cross.
15 * 16 = 240 m.
So, the train crossed 240 m length of the platform.
(13)
Abhishek said:
10 months ago
Train and man cross each other at the same direction so time is (36s-20s) = 16s.
Distance = speed * time.
Speed = 54*5/18=15m/s.
So, distance =15 * 16 =240m.
Distance = speed * time.
Speed = 54*5/18=15m/s.
So, distance =15 * 16 =240m.
(140)
Abhay Kumar said:
10 months ago
Very helpful. Thanks all for giving an explanation.
(7)
Arockiaraj said:
10 months ago
Train passes 36 sec.
Man standing 20 sec.
Train speed = 54 km/h.
platform length = ?
Train length = (54*5/18) * 36.
= 30/2 * 36.
= 30 * 18.
Train length = 540.
Platform length = (54*5/18) * 20.
= 30/2 * 20.
= 30 * 10.
= 300.
Platform length = 540 - 300.
= 240=> Ans.
Man standing 20 sec.
Train speed = 54 km/h.
platform length = ?
Train length = (54*5/18) * 36.
= 30/2 * 36.
= 30 * 18.
Train length = 540.
Platform length = (54*5/18) * 20.
= 30/2 * 20.
= 30 * 10.
= 300.
Platform length = 540 - 300.
= 240=> Ans.
(32)
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