Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
120 m
240 m
300 m
None of these
Answer: Option
Explanation:

Speed = 54 x 5 m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

x + 300 = 540

x = 240 m.

Discussion:
279 comments Page 28 of 28.

Mansi said:   5 years ago
As the man is not moving and he can be ignored as a little particle because he has not such a big length (his standing distance) as a pillar.

So if we take the time of the train passes the man, we can get the exactly length of the train.

So there, the length of the train= (15*20).

If the man would have moving, there we can't take the same length.

We are not taking the time of the platform because it has a big length which can't be ignored.

VISHESH said:   5 years ago
Time taken by train to pass a station platform = 36 seconds.
Time taken by train to pass a man on platform = 20 seconds.
Speed of train = 54 km/hr.
= ( 54 * 5/18,
= 3 * 5,
= 15 m/s.

length of train = 15 *20.
= 300 m.

Let the length of train be x.
Then;
300 + x /36 = 15.
300 + x = 15*36,
x= 540 -300,
x =260.

So, length of the platform is 240m.

Tayek said:   5 years ago
Thanks @Satheesh.

Avinash Kapu said:   5 years ago
In this problem, it is considered that the man is standing at the extreme end. That's the reason length of the train is calculated as 15*20. What if the man is standing in the middle of the platform.

Manikandan said:   5 years ago
From the given data, we can consider the only man as a reference point to find the length of train. So let us consider man is standing at the beginning, so 15*20 will be enough to find the length of the train, Am I right?

Aniket Masalkhamb said:   5 years ago
You can multiply 15 * 36 which gives you 540m then x be the length of the platform therefore as speed = distance upon time 540 +x/20 = 15.

x = 240m.

Jai said:   5 years ago
t1-t2 = 36 - 26 = 16.

We know 54 x 5/18=15,
So putting in formula s=d/t.
15 = d/16, where d is taken as length here;
d = 15 * 16,
= 240.

Keerthi said:   5 years ago
Why we, not multiple 15 * 36 instead we multiple 15 * 20? Please explain.

Sharath Naik said:   5 years ago
Why they have taken 20 sec. Can we take 30 sec also? Please explain.


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