Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = | ![]() |
54 x | 5 | m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
279 comments Page 3 of 28.
Rejwan Hossain said:
3 years ago
The length of the platform = (speed of train * time taken to pass the platform)/(1 - (time taken to pass the man/time taken to pass the platform))
In this case:
The length of platform = (54 * 36)/(1 - (20 / 36))
= (54*36)/(1-(20/36))
= (1944)/(1-(5/9))
= 1944/(4/9)
= 1944 * (9/4) = 240 meters.
In this case:
The length of platform = (54 * 36)/(1 - (20 / 36))
= (54*36)/(1-(20/36))
= (1944)/(1-(5/9))
= 1944/(4/9)
= 1944 * (9/4) = 240 meters.
(11)
Uzair said:
1 year ago
I think we don't need 20 secs a train travelling at 54km/hr took.
36 secs to pass a platform means that it covered a distance equal to. Platform in 36 secs simply convert it and the answer is 540m.
36 secs to pass a platform means that it covered a distance equal to. Platform in 36 secs simply convert it and the answer is 540m.
(11)
Adesh Katiya said:
2 years ago
t1 =36s
t2 = 20s
s= 54km/hr
l=??
d1 = s*t
d1 = 54*(5/18) * 36
d1 = 15m/s * 36
d1 = 540m.
d2 = 15*20.
d2 = 300m.3
300m is the distance up to the man standing and the length of the total platform would be greater than this. so,
300 + x = 540m.
x = 240m.
t2 = 20s
s= 54km/hr
l=??
d1 = s*t
d1 = 54*(5/18) * 36
d1 = 15m/s * 36
d1 = 540m.
d2 = 15*20.
d2 = 300m.3
300m is the distance up to the man standing and the length of the total platform would be greater than this. so,
300 + x = 540m.
x = 240m.
(10)
Aditya said:
7 months ago
540 is the total distance that includes train length+ and platform length.
Here we need only platform length that's why we need train length or you can get another approach like 36-20=16sec. It's the time of starting of the train and the starting of exist platform 15 meters per sec * 16 sec = 240 meters.
Here we need only platform length that's why we need train length or you can get another approach like 36-20=16sec. It's the time of starting of the train and the starting of exist platform 15 meters per sec * 16 sec = 240 meters.
(9)
Shobanraj said:
4 years ago
As we know Distance = Speed x Time.
Let's find the length of the train --> to find the distance of a train we have to multiply the speed of the train by the time taken by the train to cross a man or pole. so it comes like 15 x 20 = 300 meters.
So, the length of the train is 300 meters
Now when we multiply the train speed with the time taken to cross the platform..... we get the whole length of the train and also the platform length. LIKE --> 15 x 36 = 540 meters .
Now, this length is the whole length of the platform and the train.
To find the platform length subtract the train length that we found out with the whole length
300 - 540 = 240.
240 is the length of the platform.
Let's find the length of the train --> to find the distance of a train we have to multiply the speed of the train by the time taken by the train to cross a man or pole. so it comes like 15 x 20 = 300 meters.
So, the length of the train is 300 meters
Now when we multiply the train speed with the time taken to cross the platform..... we get the whole length of the train and also the platform length. LIKE --> 15 x 36 = 540 meters .
Now, this length is the whole length of the platform and the train.
To find the platform length subtract the train length that we found out with the whole length
300 - 540 = 240.
240 is the length of the platform.
(8)
Noradavis said:
3 years ago
@All.
Since the train is moving toward the man you can do 36-20 seconds = 16 seconds.
Since the train is moving toward the man you can do 36-20 seconds = 16 seconds.
(8)
Amar Mali said:
2 years ago
Thanks, everyone for explaining the answer.
(8)
Abhay Kumar said:
1 year ago
Very helpful. Thanks all for giving an explanation.
(8)
Uttam Roy said:
4 months ago
The speed of train = 54 x 5/18m/s,
= 15m/s.
Length of train = 15 x 20 = 300 meters ∴( distance = speed x time),
Total length = 15 x 30 = 540 (length of train x platform time taken to reach out),
The final answer is 540 - 300 meters.
= 240 meters.
= 15m/s.
Length of train = 15 x 20 = 300 meters ∴( distance = speed x time),
Total length = 15 x 30 = 540 (length of train x platform time taken to reach out),
The final answer is 540 - 300 meters.
= 240 meters.
(8)
Kiruthika said:
2 months ago
To find the length of the train why we use a 20-second time instead of 36 seconds? Anyone please explain to me.
(8)
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m/sec = 15 m/sec.