Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
288 comments Page 23 of 29.
Savitha said:
1 decade ago
@Vinod you have done a mistake 36-20 k be careful while doing.
Saikiran said:
2 decades ago
Length of the train = (15 x 20)m = 300 m.
how u took (15*20).
how u took (15*20).
Priyanka said:
4 years ago
D = S x T.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
(158)
Harshini said:
1 decade ago
We have the formula.
Distance = Speed*Time.
= 15*20
= 300
Distance = Speed*Time.
= 15*20
= 300
Kratika said:
5 years ago
Why didn't we added the length of the man? Please explain.
(3)
Anom said:
2 months ago
Nice explanation. Thanks to all for clarifying the answer.
Gokul said:
2 decades ago
Guys I got the answer its because.
Distance=Time*Speed.
Distance=Time*Speed.
Mansoorkhan said:
2 decades ago
Vetri great simple explanation keep it up thanks to all.
Swayoni said:
1 decade ago
Why can't we take 15*36 to find the length of the train?
Rajesh said:
8 years ago
54 * (5/18) * (36-20)=240 is the correct method I think.
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