Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
285 comments Page 23 of 29.
Priyanka said:
3 years ago
D = S x T.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
(158)
Harshini said:
1 decade ago
We have the formula.
Distance = Speed*Time.
= 15*20
= 300
Distance = Speed*Time.
= 15*20
= 300
Kratika said:
5 years ago
Why didn't we added the length of the man? Please explain.
(3)
Gokul said:
2 decades ago
Guys I got the answer its because.
Distance=Time*Speed.
Distance=Time*Speed.
Mansoorkhan said:
2 decades ago
Vetri great simple explanation keep it up thanks to all.
Swayoni said:
1 decade ago
Why can't we take 15*36 to find the length of the train?
Rajesh said:
8 years ago
54 * (5/18) * (36-20)=240 is the correct method I think.
Dipesh said:
4 years ago
54 * 5/18 = 15m/sec.
20 + 36sec = 56sec,
15 * 56 = 240m.
20 + 36sec = 56sec,
15 * 56 = 240m.
(61)
Shiva said:
2 decades ago
How is that you have taken (15 x 20) m as train length?
Gaurav pandey said:
1 decade ago
Yeah I have same question that why are we taking 15*20?
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