Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 23 of 28.
Rajesh said:
7 years ago
54 * (5/18) * (36-20)=240 is the correct method I think.
Dipesh said:
3 years ago
54 * 5/18 = 15m/sec.
20 + 36sec = 56sec,
15 * 56 = 240m.
20 + 36sec = 56sec,
15 * 56 = 240m.
(61)
Shiva said:
2 decades ago
How is that you have taken (15 x 20) m as train length?
Gaurav pandey said:
1 decade ago
Yeah I have same question that why are we taking 15*20?
Appalaraju said:
9 years ago
d = s*t;
So d = 15 m.
l = x;
x/36-20 = 15.
x = 240.
So d = 15 m.
l = x;
x/36-20 = 15.
x = 240.
Dinesh said:
1 decade ago
Man is standing on the platform how can you subtract?
Sadha said:
1 decade ago
Then what is the position of the man on the platform?
GOPAL said:
8 years ago
If you can think then,
(36-20) * 54000/3600 = 240m.
(36-20) * 54000/3600 = 240m.
Jesudas said:
7 years ago
@Sagar Dombale.
It's the conversion of km/h to m/s.
It's the conversion of km/h to m/s.
Praveen prabhakar said:
1 decade ago
Distance=speed*time
Distance=(54*5/18)*(36-20)=240m
Distance=(54*5/18)*(36-20)=240m
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