Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
285 comments Page 24 of 29.
Appalaraju said:
1 decade ago
d = s*t;
So d = 15 m.
l = x;
x/36-20 = 15.
x = 240.
So d = 15 m.
l = x;
x/36-20 = 15.
x = 240.
Dinesh said:
1 decade ago
Man is standing on the platform how can you subtract?
Sadha said:
1 decade ago
Then what is the position of the man on the platform?
GOPAL said:
9 years ago
If you can think then,
(36-20) * 54000/3600 = 240m.
(36-20) * 54000/3600 = 240m.
Jesudas said:
7 years ago
@Sagar Dombale.
It's the conversion of km/h to m/s.
It's the conversion of km/h to m/s.
Praveen prabhakar said:
1 decade ago
Distance=speed*time
Distance=(54*5/18)*(36-20)=240m
Distance=(54*5/18)*(36-20)=240m
BOMMIDIGANGABHAVANI said:
2 years ago
Here, the Length of the train = (15 x 20)m = 300 m.
(1)
Abhay Kumar said:
2 years ago
Very helpful. Thanks all for giving an explanation.
(8)
Harsh said:
2 decades ago
Difference in time=16
So ,
(16/60)*54000m/60min
So ,
(16/60)*54000m/60min
Sid said:
2 decades ago
Satheesh your answer is simply super. Thank you.
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