Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
279 comments Page 22 of 28.
Remee Rahul said:
7 years ago
Does the man standing on the starting/intial point of the platform?
Vishnu Kawale said:
4 months ago
Here, the length of the train is very small compared to real life.
(2)
Kumarchandana said:
1 decade ago
It is one of the similar way of improving our aptitude knowledge.
Lithesh kumar said:
2 years ago
Speed=54*5/18=15m/s.
Distance = 36 - 20s = 16,
=>15*16=240m.
Distance = 36 - 20s = 16,
=>15*16=240m.
(25)
Savitha said:
1 decade ago
@Vinod you have done a mistake 36-20 k be careful while doing.
Saikiran said:
2 decades ago
Length of the train = (15 x 20)m = 300 m.
how u took (15*20).
how u took (15*20).
Priyanka said:
3 years ago
D = S x T.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
D = (54x 5*18) x (36-20).
D = 15 x 16.
D = 240m/s.
(157)
Harshini said:
1 decade ago
We have the formula.
Distance = Speed*Time.
= 15*20
= 300
Distance = Speed*Time.
= 15*20
= 300
Kratika said:
4 years ago
Why didn't we added the length of the man? Please explain.
(3)
Gokul said:
2 decades ago
Guys I got the answer its because.
Distance=Time*Speed.
Distance=Time*Speed.
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