Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
288 comments Page 22 of 29.
Sabira said:
1 decade ago
S = 54*(5/18) = 15m/s.
Total time=30-20 = 16.
Length = 15*16 = 240.
Total time=30-20 = 16.
Length = 15*16 = 240.
Suraj said:
1 decade ago
First convert km/h into m/sec:
= 54*5/18 = 15.
= 15*36-15*20 = 240.
= 54*5/18 = 15.
= 15*36-15*20 = 240.
Sumithra R said:
3 months ago
Very helpful for learning the concept. Thanks, all for explaining it.
(1)
Sharath Naik said:
5 years ago
Why they have taken 20 sec. Can we take 30 sec also? Please explain.
Bharat said:
1 decade ago
v=d/t;. 15=d/36; d=540.
v=d/t ; 15=d/20 = d=300;
540-300 = 240.
v=d/t ; 15=d/20 = d=300;
540-300 = 240.
Remee Rahul said:
8 years ago
Does the man standing on the starting/intial point of the platform?
Vishnu Kawale said:
1 year ago
Here, the length of the train is very small compared to real life.
(5)
Vishakha said:
4 months ago
I think if we multiply speed with time of platform then it is 540.
Kumarchandana said:
1 decade ago
It is one of the similar way of improving our aptitude knowledge.
Lithesh kumar said:
3 years ago
Speed=54*5/18=15m/s.
Distance = 36 - 20s = 16,
=>15*16=240m.
Distance = 36 - 20s = 16,
=>15*16=240m.
(25)
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