Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
279 comments Page 21 of 28.
Krunal mistry said:
1 year ago
Why do we choose 20sec in finding distance and not 36sec?
Please explain to me.
Please explain to me.
(34)
Sridhar said:
3 years ago
Speed = 15mtr/hr.
15*20 = 15 * 36,
300 = 540.
= 540 - 300.
Length = 240.
15*20 = 15 * 36,
300 = 540.
= 540 - 300.
Length = 240.
(11)
Rabiul said:
8 years ago
What is the relation between 'standing a man 20 sec''' and 'train length''?
Bhuwan Ranjan said:
7 years ago
Answer will be 240mt but the length of the train is more than the platform.
Keerthi said:
5 years ago
Why we, not multiple 15 * 36 instead we multiple 15 * 20? Please explain.
Vrunda savaliya said:
7 years ago
First substract time =36-20 = 16.
Then,
16 * 54 * 5/18.
Length = 240m.
Then,
16 * 54 * 5/18.
Length = 240m.
Sabira said:
1 decade ago
S = 54*(5/18) = 15m/s.
Total time=30-20 = 16.
Length = 15*16 = 240.
Total time=30-20 = 16.
Length = 15*16 = 240.
Suraj said:
10 years ago
First convert km/h into m/sec:
= 54*5/18 = 15.
= 15*36-15*20 = 240.
= 54*5/18 = 15.
= 15*36-15*20 = 240.
Sharath Naik said:
5 years ago
Why they have taken 20 sec. Can we take 30 sec also? Please explain.
Bharat said:
1 decade ago
v=d/t;. 15=d/36; d=540.
v=d/t ; 15=d/20 = d=300;
540-300 = 240.
v=d/t ; 15=d/20 = d=300;
540-300 = 240.
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