Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
120 m
240 m
300 m
None of these
Answer: Option
Explanation:

Speed = 54 x 5 m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

x + 300 = 540

x = 240 m.

Discussion:
282 comments Page 20 of 29.

Rakshith said:   8 years ago
Can anybody explain me why are we taking 36-20, and Why 540-300?

Please explain this step.

Vetri said:   2 decades ago
Train passes 36 sec but man standing 20sec so (36-20=16)
speed= 15m/sec
length=16*15=240m

Kranthi said:   2 decades ago
As they asked only platform length why isn't it 35X15=540...
why should we substract...??

Bhatu said:   1 decade ago
Friends I think the actual answer is 540m, please tell me anybody it is correct or not?

Er.Shubham said:   8 years ago
@Krishna,

Don't compare the Length of both.

Take only the starting and ending point.

Ramya said:   7 years ago
Please explain, how come 15*20?

Length of the train means we have to do 15*36, right?

Noradavis said:   4 years ago
@All.

Since the train is moving toward the man you can do 36-20 seconds = 16 seconds.
(8)

Aasif Javed said:   1 decade ago
@Ashwini is your calculation right?

Please check it.

x = 54*5/18*36 = 540m not 240m

Ani said:   8 years ago
Net time = 36-20 = 16,
So length of platform is =time * speed,
That is=16x15=240 MTR.

Manonmani said:   1 decade ago
I also having doubt.

Why we took 20 sec (300=20*15).

Instead of 30sec (450=30*15).


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