Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
120 m
240 m
300 m
None of these
Answer: Option
Explanation:

Speed = 54 x 5 m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

x + 300 = 540

x = 240 m.

Discussion:
276 comments Page 20 of 28.

Er.Shubham said:   7 years ago
@Krishna,

Don't compare the Length of both.

Take only the starting and ending point.

Ramya said:   6 years ago
Please explain, how come 15*20?

Length of the train means we have to do 15*36, right?

Noradavis said:   3 years ago
@All.

Since the train is moving toward the man you can do 36-20 seconds = 16 seconds.
(8)

Aasif Javed said:   1 decade ago
@Ashwini is your calculation right?

Please check it.

x = 54*5/18*36 = 540m not 240m

Ani said:   7 years ago
Net time = 36-20 = 16,
So length of platform is =time * speed,
That is=16x15=240 MTR.

Manonmani said:   1 decade ago
I also having doubt.

Why we took 20 sec (300=20*15).

Instead of 30sec (450=30*15).

Paridhi said:   1 decade ago
Should we not consider the length of man? Why do we take it as a reference point?

Jinita said:   1 decade ago
Why took 15*20? and the method (36-20) i.e. taking difference can be applicable?

Krunal mistry said:   1 year ago
Why do we choose 20sec in finding distance and not 36sec?

Please explain to me.
(34)

Sridhar said:   3 years ago
Speed = 15mtr/hr.
15*20 = 15 * 36,
300 = 540.
= 540 - 300.
Length = 240.
(11)


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