Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
120 m
240 m
300 m
None of these
Answer: Option
Explanation:

Speed = 54 x 5 m/sec = 15 m/sec.
18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

Then, x + 300 = 15
36

x + 300 = 540

x = 240 m.

Discussion:
276 comments Page 17 of 28.

Virender Singh said:   4 years ago
Answer 240m is possible only if the man is standing at the end of the station.

Am I right or wrong? Please anyone clarify.
(6)

Divya said:   1 decade ago
I solved in dis manner
54*(5/18)=15
speed =15m/sec
it crossed d platform within 36 secs
for 20 sec=?
36-20=16
16*15=240m

Sunil Ranjan Samantaray said:   1 decade ago
Why length of the train will be 15*20 = 300?

Why not, length of train will be 15*36 = 540?

Please justify the reason.

Raghul said:   6 years ago
There is no length for man hence,
L/15 = 20.
L= 300.

And platform has length hence,
L+B/15 =36.
300+B = 540.
B=240.

Harsh said:   7 years ago
I think the answer should be 540.

Because, how can the length of the platform be less than the length of the trian?

Sara said:   2 decades ago
We can take 15x20 as the train length only if the man is standing at the beginning of the platform. Am I correct.

Reshmi said:   1 decade ago
I have the same doubt & Its not clear from all these explanations. Why you took 15*20 as the distance value?

Surender Kashyap said:   1 decade ago
L/20 = (L+P)/36 = 54*5/18
using compenondo and dividendo means (L+P)-L/36-20
P/16 = 15
SO, P = 15*16
P = 240

Kartik said:   6 years ago
54*5/18 = 15m/sec.
36-20 = 16 seconds.
Distance = speed *time.
Distance = 15m/sec*16 seconds.
Distance = 240m.

Prakash ranjan naik said:   1 decade ago
Train speed=15m/s
Time=20s
If train pass man means,that is the tme of train
That's why
Length of train=15x20


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