Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 16 of 28.
Rasik said:
1 decade ago
Guys the total time to cross the platform is 36 sec with speed of 15 m/sec i.e. d=s*t.
36*15=540 m. Hence option is none of these.
36*15=540 m. Hence option is none of these.
Ankit said:
1 decade ago
Length of man is negligible in comparison to the train, so if cal len = 20.
Then len will calculate to the train's actual lenght.
Then len will calculate to the train's actual lenght.
Frank said:
1 decade ago
Whenever u get two timings subtract the highest from the lowest.
Eg: 36 - 20 = 16
16*15 (after converting it to m/sec) = 240.
Eg: 36 - 20 = 16
16*15 (after converting it to m/sec) = 240.
Sibu said:
1 decade ago
If the man is at starting point of platform then answer is 240.
If the man is at any where of the platform then answer is 540.
If the man is at any where of the platform then answer is 540.
Abhi singh said:
6 years ago
54 * 5/18 = 15.
You have values than 36-20 after you get=16, now
15*16 = 240m/s,
And this is easily finding your ans = 240m/s.
You have values than 36-20 after you get=16, now
15*16 = 240m/s,
And this is easily finding your ans = 240m/s.
Satheesh.m said:
1 decade ago
Speed as we calculated 15m/sec
The difference from the ref pt (i.e.,man) to the train pass the platform is 16
So, 15*16=240m
The difference from the ref pt (i.e.,man) to the train pass the platform is 16
So, 15*16=240m
Kirankumar said:
1 decade ago
Hi afkhan according to nick
The train takes to cross it self 20
The remaining 16 for platform
Refer point no 4 in formulae.
The train takes to cross it self 20
The remaining 16 for platform
Refer point no 4 in formulae.
Mounika said:
7 years ago
First we convert to m/s.
54 * (5/18)=15m/s.
We know that length=speed * time.
=15 * (net time),
=15 * (36-20).
=15 * 16=240,
54 * (5/18)=15m/s.
We know that length=speed * time.
=15 * (net time),
=15 * (36-20).
=15 * 16=240,
Rahul said:
1 decade ago
We can do it like this.
Train run in 36sec, so 36 * 15 = 540. Train run in 20 sec, so 20 * 15 = 300.
Ans: 540 - 300 = 240.
Train run in 36sec, so 36 * 15 = 540. Train run in 20 sec, so 20 * 15 = 300.
Ans: 540 - 300 = 240.
Manoj dhawade said:
1 decade ago
We have to do 15*(36-20) because train crosses the platform in 36 sec and the man in 20 sec. So the answer should be 240 m.
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