Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 15 of 28.
Jagadeesh said:
1 decade ago
Hey guys u can do like this u can take the diffeerence between times i.e 36-20=16 seconds
u can change 54km/hr as meters 54*5/18=15
16*15=240meters
u can change 54km/hr as meters 54*5/18=15
16*15=240meters
MOHAMED YAZAR S said:
2 years ago
Speed = 54km/hr
54*5/18 = 15m/s.
Time = 36-20 =16sec.
Length of the platform(D)=?
Distance = speed * time.
Distance = 15 * 16.
Distance = 240 m.
54*5/18 = 15m/s.
Time = 36-20 =16sec.
Length of the platform(D)=?
Distance = speed * time.
Distance = 15 * 16.
Distance = 240 m.
(222)
Srikanth said:
1 decade ago
Speed=54*(5/18)=15m/s.
Now time = 36-20=16.
Now distance(i.e length)=speed*time
=15*16
=240m/s.
Now time = 36-20=16.
Now distance(i.e length)=speed*time
=15*16
=240m/s.
Avinash said:
1 year ago
Here already taken by speed in 15m/sec.
And train length 15 × 20 = 300 m.
Then why take by the agin 15m/sec× 36 seconds can you explain this?
And train length 15 × 20 = 300 m.
Then why take by the agin 15m/sec× 36 seconds can you explain this?
(7)
Jackiep said:
5 years ago
Time taken to pass a station = 36s.
Time taken to pass a man = 20s.
Difference=16s.
We have,
Distance = Speed X Time.
= 15 X 16.
= 240m.
Time taken to pass a man = 20s.
Difference=16s.
We have,
Distance = Speed X Time.
= 15 X 16.
= 240m.
(1)
Jai said:
4 years ago
t1-t2 = 36 - 26 = 16.
We know 54 x 5/18=15,
So putting in formula s=d/t.
15 = d/16, where d is taken as length here;
d = 15 * 16,
= 240.
We know 54 x 5/18=15,
So putting in formula s=d/t.
15 = d/16, where d is taken as length here;
d = 15 * 16,
= 240.
Agnel said:
7 years ago
Speed=54*5÷18=15.
:.15*20=300,
15*36=540,
--------------------
240.
Another option;
Speed 15.
36-20=16,
.:15*16=240.
:.15*20=300,
15*36=540,
--------------------
240.
Another option;
Speed 15.
36-20=16,
.:15*16=240.
RAMKUMAR said:
7 years ago
Speed=54*5 ÷ 18=15.
:.15*20=300,
15*36=540,
--------------------
240.
Another option;
Speed 15.
36-20=16,
Therefore, 15 * 16 = 240.
:.15*20=300,
15*36=540,
--------------------
240.
Another option;
Speed 15.
36-20=16,
Therefore, 15 * 16 = 240.
Veera said:
1 decade ago
They have asked for total length of the platform and answer must be 300+240 = 540 mt. Am I right ? can anyone help me clear my doubt.
Sahil shaikh said:
5 years ago
The train passes a station 36.
Man on platform 20.
Loss of time man 36-20=16.
Speed = distance/time.
15m/sec = L/16.
15x16 = 240 m.
Man on platform 20.
Loss of time man 36-20=16.
Speed = distance/time.
15m/sec = L/16.
15x16 = 240 m.
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