Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 14 of 28.
Gaurav said:
1 decade ago
Can we do it on this way.
In 36 second train run 36 x 15 = 540 m.
In 20 second train run 20 x 15 = 300 m.
And the length of platform is 540 - 300 = 240 mtr.
In 36 second train run 36 x 15 = 540 m.
In 20 second train run 20 x 15 = 300 m.
And the length of platform is 540 - 300 = 240 mtr.
Abhishek said:
10 months ago
Train and man cross each other at the same direction so time is (36s-20s) = 16s.
Distance = speed * time.
Speed = 54*5/18=15m/s.
So, distance =15 * 16 =240m.
Distance = speed * time.
Speed = 54*5/18=15m/s.
So, distance =15 * 16 =240m.
(140)
Cristianomahesh said:
9 years ago
Hii guys, I think.
Length = speed * time.
We have to find platform length so we have taken the man standing on platform time.
Therefore, length = 15 * 20.
Length = speed * time.
We have to find platform length so we have taken the man standing on platform time.
Therefore, length = 15 * 20.
Thiyagu said:
9 years ago
54 * (5/18) = 15m.
x = 36s y = 20s.
x - y = 16s (dist b/w train reach the station - train reach the man).
Now,
15 * 16 = 240m (speed * dist).
Answer = 240m.
x = 36s y = 20s.
x - y = 16s (dist b/w train reach the station - train reach the man).
Now,
15 * 16 = 240m (speed * dist).
Answer = 240m.
Remy said:
1 decade ago
How come (300+x) /15?its not said the man stands at the beginning of platform. If hes somwhere in the middle how come we add the length of the train 300 m ?
Suganthan.m said:
1 decade ago
Hi Guys
speed=15 m/s
A train passes the platform in 36 secs
15*36=540
a man standing on the platform in 20 secs
15*20=300
540-300=240
Ans:240 Am I right
speed=15 m/s
A train passes the platform in 36 secs
15*36=540
a man standing on the platform in 20 secs
15*20=300
540-300=240
Ans:240 Am I right
Syed zubair said:
5 years ago
Just subtract the time taken by train to pass a man with the time taken by a train to pass a station i.e 36-20 = 16.
16*15(speed in meters) = 240 meters.
16*15(speed in meters) = 240 meters.
Rahul said:
1 decade ago
Please tell me the reason why we can not calculate lenght of train through 15*36=540 can we calculate lenght of train like this if nt thn tell me reason.
Ramkumar said:
1 decade ago
Speed = 54*(5/18) = 15m/s.
Now time = 36-20 = 16.
Now distance(i.e length) = speed*time.
= 15*16.
= 240m/s.
This is way of correct. Please explain.
Now time = 36-20 = 16.
Now distance(i.e length) = speed*time.
= 15*16.
= 240m/s.
This is way of correct. Please explain.
Aniket Masalkhamb said:
4 years ago
You can multiply 15 * 36 which gives you 540m then x be the length of the platform therefore as speed = distance upon time 540 +x/20 = 15.
x = 240m.
x = 240m.
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