Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
282 comments Page 13 of 29.
Austin said:
1 decade ago
Hello guys you can this problem in this way also.
Train Time = 36 second.
Men time = 20 second.
(36-20) = 16.
Speed = 54km/hr
54*5/18 = 15ms.
Distance = 15*16 = 240m.
Train Time = 36 second.
Men time = 20 second.
(36-20) = 16.
Speed = 54km/hr
54*5/18 = 15ms.
Distance = 15*16 = 240m.
Vivek said:
2 decades ago
speed:- 54*5/18= 15 m/sec
length of the train:-15*20= 300 m.(distance= speed * time)
length of the platform:-x
Speed = Distance /Time
15=300+x/36
300+x=540
x=540-300
x=240
length of the train:-15*20= 300 m.(distance= speed * time)
length of the platform:-x
Speed = Distance /Time
15=300+x/36
300+x=540
x=540-300
x=240
Vicky said:
1 decade ago
@Suraj we can also apply direct formula of speed on 15.
= 54*5/18 = 15.
Speed = Distance/Time.
15 = X/36-20.
X = 240.
Here 36-20 because both are in towards direction.
= 54*5/18 = 15.
Speed = Distance/Time.
15 = X/36-20.
X = 240.
Here 36-20 because both are in towards direction.
Mohammed ali said:
1 decade ago
Hai friend I will put in another way you will sub higher to lower 36-20 you will get 16 answer and you can multiple:
16*54 = 864.
= 864*5/18.
= 4320/18.
= 240 answer.
16*54 = 864.
= 864*5/18.
= 4320/18.
= 240 answer.
Praveen said:
1 decade ago
s = d/ t.
Length of train = s*t = 15 m/sec*20 sec = 300 m.
Now let length of platform = x m.
Total length = (300+x) m.
s = d/t.
15 = 300+x/36.
As 123 answer = 250 m
Length of train = s*t = 15 m/sec*20 sec = 300 m.
Now let length of platform = x m.
Total length = (300+x) m.
s = d/t.
15 = 300+x/36.
As 123 answer = 250 m
Harry said:
10 years ago
SIMPLE WAY.
Speed = 54km/hr,
54/3600 * 1000,
=15m/s.
36 sec to pass the platform
15 * 36 = 540.
20 sec to pass the man,
15 * 20 = 300.
i.e distance is 540 - 300 = 240.
Speed = 54km/hr,
54/3600 * 1000,
=15m/s.
36 sec to pass the platform
15 * 36 = 540.
20 sec to pass the man,
15 * 20 = 300.
i.e distance is 540 - 300 = 240.
Ravinder Kumar said:
1 decade ago
The simple method is
Train speed is 54km/h*5/18=15m/second
Time taken between man standing on platform and station platform ( 36-20) = 16 sec.
Distance= 15*16 = 240m
Train speed is 54km/h*5/18=15m/second
Time taken between man standing on platform and station platform ( 36-20) = 16 sec.
Distance= 15*16 = 240m
Shubham Gupta said:
1 decade ago
s = d/ t.
Length of train = s*t = 15 m/sec*20 sec = 300 m.
Now let length of platform = x m.
Total length = (300+x) m.
s = d/t.
15 = 300+x/36.
x = 240 m answer.
Length of train = s*t = 15 m/sec*20 sec = 300 m.
Now let length of platform = x m.
Total length = (300+x) m.
s = d/t.
15 = 300+x/36.
x = 240 m answer.
Praveen R said:
1 decade ago
Time taken for reach the platform=36sec.
Time taken for reach a man= 16sec.
Speed (S) = (54*5) /18=15.
Distance between=36-20=16.
Then the distance=16*15.
=240.
Time taken for reach a man= 16sec.
Speed (S) = (54*5) /18=15.
Distance between=36-20=16.
Then the distance=16*15.
=240.
Magesh said:
2 decades ago
Guys listen.
Take a point as man standing on the platform. So the moving train pass the point at the time of 20 sec.
So, Length of the train = (15 x 20)m = 300 m.
Take a point as man standing on the platform. So the moving train pass the point at the time of 20 sec.
So, Length of the train = (15 x 20)m = 300 m.
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