Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
276 comments Page 12 of 28.
Cnine said:
6 years ago
The second method is, Convert the speed in m/sec.
And man is standing in platform then the both given time is subtract to each other and the subtract answer is multiplied the speed.
And man is standing in platform then the both given time is subtract to each other and the subtract answer is multiplied the speed.
Kabita said:
1 decade ago
Train passes in 36 secs, man standing in 20 secs.
Therefor, 36-20= 16 secs.
Now, speed = 54 km/hr.
= {54 X 5/18} = 15 m/sec.
Here, length = speed X time
= 15 X 16
= 240 m. ans
Therefor, 36-20= 16 secs.
Now, speed = 54 km/hr.
= {54 X 5/18} = 15 m/sec.
Here, length = speed X time
= 15 X 16
= 240 m. ans
Nagashree said:
1 decade ago
Here man is standing in the platform, and we have to calculate the length of platform.
Hence we hav to multiply by 20 & not by36. Man in platform is reference point to us.
Hence we hav to multiply by 20 & not by36. Man in platform is reference point to us.
Veeresh said:
1 decade ago
xkmph means train goes x meters in 3.6 seconds. here 36-20secs required to travel for the train to pass platform.
3.6 sec---->54 meters
16 secs---->?
16/3.6x54=240 meters
3.6 sec---->54 meters
16 secs---->?
16/3.6x54=240 meters
Udaya said:
1 decade ago
We can also do like this guyz.
Total time taken to cross the platform = 36-20 = 16.
Because the person is in the platform which the train crosses.
Now length= 15*16 = 240m.
Total time taken to cross the platform = 36-20 = 16.
Because the person is in the platform which the train crosses.
Now length= 15*16 = 240m.
Mastan said:
2 years ago
Let's take the train length for the man and station platform the same, then
D = D.
S * t = s * t.
15 * 36 = 15 * 20,
540 = 300.
540 - 300.
240.
Speed conversion 54 * 5/18 = 15.
D = D.
S * t = s * t.
15 * 36 = 15 * 20,
540 = 300.
540 - 300.
240.
Speed conversion 54 * 5/18 = 15.
(61)
Guru said:
1 decade ago
The time taken by train to cross platform is=36-20=16sec.
Speed of train=54*(5/18)m/s.
Distance(length)=speed*time.
=54*(5/18)*16.
=240m.
Speed of train=54*(5/18)m/s.
Distance(length)=speed*time.
=54*(5/18)*16.
=240m.
Austin said:
1 decade ago
Hello guys you can this problem in this way also.
Train Time = 36 second.
Men time = 20 second.
(36-20) = 16.
Speed = 54km/hr
54*5/18 = 15ms.
Distance = 15*16 = 240m.
Train Time = 36 second.
Men time = 20 second.
(36-20) = 16.
Speed = 54km/hr
54*5/18 = 15ms.
Distance = 15*16 = 240m.
Vivek said:
1 decade ago
speed:- 54*5/18= 15 m/sec
length of the train:-15*20= 300 m.(distance= speed * time)
length of the platform:-x
Speed = Distance /Time
15=300+x/36
300+x=540
x=540-300
x=240
length of the train:-15*20= 300 m.(distance= speed * time)
length of the platform:-x
Speed = Distance /Time
15=300+x/36
300+x=540
x=540-300
x=240
Vicky said:
10 years ago
@Suraj we can also apply direct formula of speed on 15.
= 54*5/18 = 15.
Speed = Distance/Time.
15 = X/36-20.
X = 240.
Here 36-20 because both are in towards direction.
= 54*5/18 = 15.
Speed = Distance/Time.
15 = X/36-20.
X = 240.
Here 36-20 because both are in towards direction.
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