Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
282 comments Page 11 of 29.
Uvesh said:
9 years ago
I did it like this.
First, while train passing thru platform in 36 sec = 15 x 36 = 540,
Second while train passing thru man in 20sec = 15 x 20 = 300,
Now, the relative length 540 - 300 = 240.
First, while train passing thru platform in 36 sec = 15 x 36 = 540,
Second while train passing thru man in 20sec = 15 x 20 = 300,
Now, the relative length 540 - 300 = 240.
Peter said:
10 years ago
Easily way.
Train speed is 54 in KM/HR so KM/HR = 1000 M /3600 S = 10/36 = 5/18 * 54 train speed = 15 M/S.
Train crossed in 36 man in 20 so we can minus both so 36 - 20 = 16.
16 * 15 = 240.
Train speed is 54 in KM/HR so KM/HR = 1000 M /3600 S = 10/36 = 5/18 * 54 train speed = 15 M/S.
Train crossed in 36 man in 20 so we can minus both so 36 - 20 = 16.
16 * 15 = 240.
Krishna said:
8 years ago
Here, the length of the train is more than the length of the platform, how can a train be fit on that platform?
Platform length is 240m and Train length is 300m. Please explain me about it.
Platform length is 240m and Train length is 300m. Please explain me about it.
Srinivas said:
1 decade ago
Actually, here it is asked for platform and train passed the platform. It doesn't matter train passed the man's distance. It's simple L = S*T but why you are including passed by man's time?
Bhaskar said:
9 years ago
When the train enters fully from where the platform begins and at the beginning point where the man is standing it takes 20 sec so,
=54*5/18*20= 300 and that is the length of the train.
=54*5/18*20= 300 and that is the length of the train.
Lokesh said:
3 years ago
Given the speed of the train is 54 km/hr.
In 60*60second.
15m in 1 seconds.
90m in 6 seconds.
150m in 10 seconds.
240m in 16 seconds.
Because the time diff is 16 seconds Platform length.
In 60*60second.
15m in 1 seconds.
90m in 6 seconds.
150m in 10 seconds.
240m in 16 seconds.
Because the time diff is 16 seconds Platform length.
(30)
Shivam singh said:
8 years ago
Km/h to m/s.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
So,
54kmph = 54*5/18 = 15m/s.
The Length of platform = speed * time difference (because 20 is referral point)
= 15 * (36 - 20) = 240m.
Suraj said:
7 years ago
Here, it is solved by taking 15*20 but why?
20 is speed of man not a train. We are taking into account that speed of train. If we take the speed of train then answer will becomes zero.
20 is speed of man not a train. We are taking into account that speed of train. If we take the speed of train then answer will becomes zero.
Ravi Kumar said:
4 years ago
The length of platform = x + 300/36 = 15 m/s.
Can someone explain why we write the 15 m/s on R.H.S of the equation?
I really could not understand. If someone knows then please help me.
Can someone explain why we write the 15 m/s on R.H.S of the equation?
I really could not understand. If someone knows then please help me.
(5)
Mamtha said:
1 decade ago
The train pass the man 20sec, and the train pass a station 36sec.
So,36-20=16sec
Then we know that speed of the train of the train is 54km/hr.
=15m/sec
Therefore, 16*15=240m. Answer.
So,36-20=16sec
Then we know that speed of the train of the train is 54km/hr.
=15m/sec
Therefore, 16*15=240m. Answer.
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