Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 5)
5.
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option
Explanation:
| Speed = |  |
54 x | 5 |  m/sec = 15 m/sec. |
| 18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
| Then, | x + 300 | = 15 |
| 36 |
x + 300 = 540
x = 240 m.
Discussion:
282 comments Page 18 of 29.
Surender Kashyap said:
1 decade ago
L/20 = (L+P)/36 = 54*5/18
using compenondo and dividendo means (L+P)-L/36-20
P/16 = 15
SO, P = 15*16
P = 240
using compenondo and dividendo means (L+P)-L/36-20
P/16 = 15
SO, P = 15*16
P = 240
Kiruthika said:
8 months ago
To find the length of the train why we use a 20-second time instead of 36 seconds? Anyone please explain to me.
(22)
Kartik said:
7 years ago
54*5/18 = 15m/sec.
36-20 = 16 seconds.
Distance = speed *time.
Distance = 15m/sec*16 seconds.
Distance = 240m.
36-20 = 16 seconds.
Distance = speed *time.
Distance = 15m/sec*16 seconds.
Distance = 240m.
Prakash ranjan naik said:
1 decade ago
Train speed=15m/s
Time=20s
If train pass man means,that is the tme of train
That's why
Length of train=15x20
Time=20s
If train pass man means,that is the tme of train
That's why
Length of train=15x20
Tina said:
1 decade ago
Total time = 36sec - 20sec = 16 sec.
Speed = 54*(5/18) = 15 m/sec.
Length = speed * time = 15 * 16 = 240m.
Speed = 54*(5/18) = 15 m/sec.
Length = speed * time = 15 * 16 = 240m.
R.sai said:
1 decade ago
Another method we do that problem.
Train reach time-man standing time = 36-20 = 16.
Length = 15*16 = 240m.
Train reach time-man standing time = 36-20 = 16.
Length = 15*16 = 240m.
Sai said:
10 years ago
Length = Speed * Time.
Speed = 54 * 5/18 = 15 m/sec.
Time = 36 - 20 = 16.
Length = 15 * 16.
= 240m.
Speed = 54 * 5/18 = 15 m/sec.
Time = 36 - 20 = 16.
Length = 15 * 16.
= 240m.
Shelke ganesh mariba said:
7 years ago
According to speed of trai = 15m/s.
And time = 36-20 = 16sec.
Therefore length of platform = 15x16 = 240m.
And time = 36-20 = 16sec.
Therefore length of platform = 15x16 = 240m.
Sravana said:
7 years ago
D = TxS.
As we mentioned here,
54kmph = 54x(5÷18) = 15mps.
D = TxS.
= (36-20)x15.
= 16x15.
= 240mts.
As we mentioned here,
54kmph = 54x(5÷18) = 15mps.
D = TxS.
= (36-20)x15.
= 16x15.
= 240mts.
Varad shinde said:
9 years ago
He guys,
In the problem, there is a common formula used from the examiner is,
Distance = Speed x Time.
In the problem, there is a common formula used from the examiner is,
Distance = Speed x Time.
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