Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 20 of 21.
Saji said:
2 decades ago
Kumar thanks a lot. You cleared my doubt. I am confusing this concept for long time.
IndiaBIX said:
2 decades ago
Well said Kumar.
Here 240m is the length of train, 650m is the length of Platform.
If we don't add 240m, we can only calculate the time taken by the part of engine to cross the bridge, not by the entire train.
That's why we are adding length of the train to platform length (distance = length of train + length of platform).
Reference: Important Formulas - Problems on Trains
Here 240m is the length of train, 650m is the length of Platform.
If we don't add 240m, we can only calculate the time taken by the part of engine to cross the bridge, not by the entire train.
That's why we are adding length of the train to platform length (distance = length of train + length of platform).
Reference: Important Formulas - Problems on Trains
Kumar said:
2 decades ago
Hi Saji,
You are wrong.
We have to add the length of the train to the length of the platform in order to find the time taken to 'cross the bridge'.
In case of crossing a man/post/pole:
Usually we will ignore the length of man/post/pole. If you want the result speed in 'milli meters/second' accuracy, you can add length of the man or pole to the length of the train.
You are wrong.
We have to add the length of the train to the length of the platform in order to find the time taken to 'cross the bridge'.
In case of crossing a man/post/pole:
Usually we will ignore the length of man/post/pole. If you want the result speed in 'milli meters/second' accuracy, you can add length of the man or pole to the length of the train.
(1)
Saji said:
2 decades ago
There is no need of adding 240 and 650..because the question is to calculte the time taken by train to cross the bridge...
so after finding the speed of the train v can calculate directly the time taken by the train by
time=dis/speed
time=650/10
time=65 sec
this may be correct..please suggest me an exact reason why we are adding 650 to 240
so after finding the speed of the train v can calculate directly the time taken by the train by
time=dis/speed
time=650/10
time=65 sec
this may be correct..please suggest me an exact reason why we are adding 650 to 240
Rashid said:
2 decades ago
But the train is standing on the platform itself, so its length is included in platform length? what is the need to add 24 and 650.
Sujitha said:
2 decades ago
Speed= (240*1000)/3600
Do we can calculate like this? is this correct?
Do we can calculate like this? is this correct?
Yuvi said:
2 decades ago
It may correct. 89sec.
Aditya said:
2 decades ago
I think answer is 65 sec. Why did you add 240 and 650 no need to add?
Kirubanidhi said:
2 decades ago
First we find speed of the train
speed=distance/time ;distance=240m,time=24 sec
speed= 10 m/sec
the question is how long the train pass the 650m platform
so time = distance/speed;
=(240+650)/10 m/s
=89 sec
speed=distance/time ;distance=240m,time=24 sec
speed= 10 m/sec
the question is how long the train pass the 650m platform
so time = distance/speed;
=(240+650)/10 m/s
=89 sec
Ramesh karthick said:
2 decades ago
No. It not pass poles and platform. It pass only platform. 240m is train length.
(1)
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