Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 15 of 21.
Akhila said:
1 decade ago
@Pooja.
Here we must add 240. Because the total length is expressed as length of the train + length of the platform.
(i.e) 240+650=890.
Here we must add 240. Because the total length is expressed as length of the train + length of the platform.
(i.e) 240+650=890.
Pooja said:
1 decade ago
Can any tell me why there is need to add 240 ?
Vijay said:
1 decade ago
How can u know that the pole is on the platform.
if the pole is not on the platform,the ans is 65
240/24=650/t2
t2=65
if the pole is not on the platform,the ans is 65
240/24=650/t2
t2=65
Vijay said:
1 decade ago
As per the given data,the question didn't tell about the pole is on the platform or not.
so,speed = distance/time
speed = 240m/24sec
= 10 m/sec
here speed is same to cross platform as well as pole
so,
D1/T1 = D2/T2
240m/24sec = 640m/T2
10 = 640/T2
T2 = 64 sec
so,speed = distance/time
speed = 240m/24sec
= 10 m/sec
here speed is same to cross platform as well as pole
so,
D1/T1 = D2/T2
240m/24sec = 640m/T2
10 = 640/T2
T2 = 64 sec
Swetha said:
1 decade ago
Here no need of calculating the speed, as speed is same we can directly calculate as below:
(d1/t1) = (d2/t2).
(240/24) = ((240+650) /x).
X=89sec.
(d1/t1) = (d2/t2).
(240/24) = ((240+650) /x).
X=89sec.
Rasim said:
1 decade ago
We can calculate the train speed by considering pole as a reference point
train length=240m
time taken by a train to pass a pole =24sec
s=d/t
s=(240/24)
s=10m/sec
platform length=650m
we know that
total distance=speed*time
650+240=10*t
890=10*t
t=89sec
train length=240m
time taken by a train to pass a pole =24sec
s=d/t
s=(240/24)
s=10m/sec
platform length=650m
we know that
total distance=speed*time
650+240=10*t
890=10*t
t=89sec
Ravi said:
1 decade ago
I am done my way.
If its takes 24s to cross 240m,
So how much it'l take to cross 650m long platform. 240+650=890.
You just put one equation like.
240m=24s.
890m=?, then cross multiplication.
890*24/240=89.
If its takes 24s to cross 240m,
So how much it'l take to cross 650m long platform. 240+650=890.
You just put one equation like.
240m=24s.
890m=?, then cross multiplication.
890*24/240=89.
Satish said:
1 decade ago
Train of length 240 mts.....
It covers 240 mts in 24 sec...
During crossing a bridge it has to cover 650 mts additional to 240....
So 240mts in 24 sec
Then (240+650) in x sec
i.e x=24*890/240===>89
It covers 240 mts in 24 sec...
During crossing a bridge it has to cover 650 mts additional to 240....
So 240mts in 24 sec
Then (240+650) in x sec
i.e x=24*890/240===>89
Varun Kumar Saraswat said:
1 decade ago
Total distance= Total length of train + Length of platform
Vino said:
1 decade ago
@sonal,
First we find the TIME of the train. So we get 240/24=10m/1s.
Next we find the total DISTANCE of the train. So we get 240+650=890.
Finally.
Speed=distance/time.
=890/10.
=89sec.
First we find the TIME of the train. So we get 240/24=10m/1s.
Next we find the total DISTANCE of the train. So we get 240+650=890.
Finally.
Speed=distance/time.
=890/10.
=89sec.
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