Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 11 of 21.
Mallikarjun said:
1 decade ago
24 ........> 240.
? ........> 240+650 = 890.
89 sec.
? ........> 240+650 = 890.
89 sec.
Nagesh Shirsat said:
1 decade ago
Well the question is how long train take to cross the platform, in order to do so, train has to cover total length of platform i.e. 650 m and its own length i.e. 240 m, hence 240+650/10=89. 65 is when the engine crosses the platform, it has got to travel train length too to cross the platform entirely. I hope all doubts are clear now.
Bunny said:
1 decade ago
By adding 240+650, it says the distance travelled by the whole train to cross the platform.
Rajesh lodhi said:
1 decade ago
Please solve this question.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
Divyan said:
1 decade ago
Why we can't minus 240 and 650. Please. Help me to know when should we add and when should we minus?
What is the meaning of engine crossing in 65?
What is the meaning of engine crossing in 65?
K.anusha said:
1 decade ago
Please explain 240+650/10?
Basavaraj S G said:
1 decade ago
Hello guys.
W.k.t, speed = dist/time.
So on comparing,
Dist/time = dist/time.
240/24 = (240+650)/t.
t = (890/24)/240.
t = 89 sec.
W.k.t, speed = dist/time.
So on comparing,
Dist/time = dist/time.
240/24 = (240+650)/t.
t = (890/24)/240.
t = 89 sec.
Manoj said:
1 decade ago
Time taken by a train of length l meters to pass a stationery object of length b meters is the time taken by the train to cover (l + b) meters.
So its (650+240)/100.
So its (650+240)/100.
Arun said:
1 decade ago
I think that if they asked how long it will take to cross the pole and platform means 89 is correct but platform alone means 65 because speed of the trains 10m/s.
Sudarsan said:
1 decade ago
Given train distance is = 240 m.
Platform distance = 650 m.
Speed of train = 240/24= 10 m/s.
Let the platform be AB = 650 m.
And train length be CD = 240 m.
The time taken is 65 s for D of the train (the front part).
Thus for the train to completely pass i.e. C to pass the total distance is (240 + 650 m).
Thus time taken for the train to pass is 89 s.
Platform distance = 650 m.
Speed of train = 240/24= 10 m/s.
Let the platform be AB = 650 m.
And train length be CD = 240 m.
The time taken is 65 s for D of the train (the front part).
Thus for the train to completely pass i.e. C to pass the total distance is (240 + 650 m).
Thus time taken for the train to pass is 89 s.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers