Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 10 of 21.
Sikkanthar said:
1 decade ago
Here the aim of this problem is to be calculate the time taken of the train to cross 650 m long platform.
So from the given data (distance and time) , we have to calculate what is speed of the train.
(distance or length) / time = speed.
So we can calculate the value of speed.
You don't need to convert into hr. Because you are going to find out the time "in s" so you'll get the answer.
I hope anyone understand how do solve this kind of problems.
So from the given data (distance and time) , we have to calculate what is speed of the train.
(distance or length) / time = speed.
So we can calculate the value of speed.
You don't need to convert into hr. Because you are going to find out the time "in s" so you'll get the answer.
I hope anyone understand how do solve this kind of problems.
Gaurav said:
1 decade ago
I think the data in not correct because they were asking to pass only 650m long. But here they are taken 650 + 240 which no where written to take.
Sudipta said:
1 decade ago
If the train cross the platform i.e it crosses own length.
(own length 240 + Platform 650) = / 24 time = 89 sec its correct.
(own length 240 + Platform 650) = / 24 time = 89 sec its correct.
Rajesh said:
1 decade ago
240 m in 24 seconds.
So one second 10 m.
So platform length 650 m. It means the train just reach the end of the platform in 650 seconds. It means train not pass the platform. 240 m train is in platform. Its also going to pass.
So 650+240 = 890 m so. 89 sec. is the answer.
So one second 10 m.
So platform length 650 m. It means the train just reach the end of the platform in 650 seconds. It means train not pass the platform. 240 m train is in platform. Its also going to pass.
So 650+240 = 890 m so. 89 sec. is the answer.
Jitendra barod said:
1 decade ago
Speed = 240/24 = 10.
Speed = total distance/time.
Time = total distance/speed = (240+650)/10 = 89 sec.
Speed = total distance/time.
Time = total distance/speed = (240+650)/10 = 89 sec.
Kishor said:
1 decade ago
For speed of the train (assume Z).
[distance = speed x time].
240 = Z x 24.
Z = 240/24.
Z = 10m/sec.
Let assume time is Y,
Length of the platform = (speed x time) - length of train.
650 = (10xY)-240.
Y = (650+240)/10.
Y = 89sec.
[distance = speed x time].
240 = Z x 24.
Z = 240/24.
Z = 10m/sec.
Let assume time is Y,
Length of the platform = (speed x time) - length of train.
650 = (10xY)-240.
Y = (650+240)/10.
Y = 89sec.
Leela venkateswara aro said:
1 decade ago
Let length of the train=l=240m.
Time taken to cross platform=t=?
Platform length=a=650m.
Speed of the train=S= (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s =240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
During this time the train has to cross its own length as well as platform length.
Time taken to cross platform=t=?
Platform length=a=650m.
Speed of the train=S= (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s =240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
During this time the train has to cross its own length as well as platform length.
Vatsal Patel said:
1 decade ago
I think many people are confusing why we add train length here. The train crosses the bridge means that initially its engine was at starting of the bridge and when it has crossed the bridge, the last bogy of the train is on the other end of the bridge. And engine will be quite ahead by the length of train. So actually the train travels the distance 240+650 in this case when we consider only its engine for ease.
Pon said:
1 decade ago
Let length of the train = l = 240m.
Time taken to cross platform = t = ?
Platform length = a = 650m.
Speed of the train = S = (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s = 240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
Time taken to cross platform = t = ?
Platform length = a = 650m.
Speed of the train = S = (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s = 240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
Chandu said:
1 decade ago
I got a doubt!
Train length = 240m.
Here in this case platform is independent of train length it is just the speed!
So I feel 65 sec is the answer.
Any suggestions please!
Train length = 240m.
Here in this case platform is independent of train length it is just the speed!
So I feel 65 sec is the answer.
Any suggestions please!
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