Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 9 of 59.
Madhav Kulkarni said:
6 years ago
Train Speed is 60km/h ----- 60*(5/18)---------16.66 m/s.
time taken to cross the pole=9sec.
S=Distance(Length)/time.
s=16.66 time=9.
Distance(Length)=Speed*Time = 16.66*9 = 149.94 ===150.
So, Length = 150m.
time taken to cross the pole=9sec.
S=Distance(Length)/time.
s=16.66 time=9.
Distance(Length)=Speed*Time = 16.66*9 = 149.94 ===150.
So, Length = 150m.
Adesh Katiya said:
2 years ago
s = 60km/hr
Time to cross pole = 9sec.
l = ?.
Time(train of length l) (pass a pole) = time(to cover l meters).
So,
9s = dist(l)/60km/hr
9s = dist(l)/1/6ms
9s = 6*dist
3/2 = dist
1.5 = dist
Hence option (d).
Time to cross pole = 9sec.
l = ?.
Time(train of length l) (pass a pole) = time(to cover l meters).
So,
9s = dist(l)/60km/hr
9s = dist(l)/1/6ms
9s = 6*dist
3/2 = dist
1.5 = dist
Hence option (d).
(10)
Susi said:
1 year ago
Speed 60 km/hr.
Time = 9 sec.
1. Convert speed into m/sec.
ie, Speed/3.6 => 60/3.6=16.67 m/sec.
2. To find the length.
Length L =Speed x time.
ie, L= 16.67 x 9 =150.
So the length of the train is 150 m.
Time = 9 sec.
1. Convert speed into m/sec.
ie, Speed/3.6 => 60/3.6=16.67 m/sec.
2. To find the length.
Length L =Speed x time.
ie, L= 16.67 x 9 =150.
So the length of the train is 150 m.
(15)
Rayees Khan Aryan said:
8 years ago
Length of a Train.
T = (LT+LP)/S
LT = LENGTH OF A TRAIN = ?
LP = LENGTH OF A PLATFORM = 0
S = SPEED = (60*5)/18 = 50/3
T= TIME= 9.
NOW AS PER THE QUESTION.
9 = (?+0)/ (50/3),
=> ? = (9 * 50)/3 = 150 M.
T = (LT+LP)/S
LT = LENGTH OF A TRAIN = ?
LP = LENGTH OF A PLATFORM = 0
S = SPEED = (60*5)/18 = 50/3
T= TIME= 9.
NOW AS PER THE QUESTION.
9 = (?+0)/ (50/3),
=> ? = (9 * 50)/3 = 150 M.
Jagadeesh said:
1 decade ago
Here, give train travels at a speed of (60*5/18) m/s, that is for one second it travels a distance of 50/3 m/s. So the distance traveled for 9 seconds gives the actual length of train, that is 50/3*9=150m.
Rajneesh said:
7 years ago
Speed = Ditance/Time.
Distance = Speed * Time.
Or lenght = Speed * Time .
=( 60 *5/18) * 9,
= 50/3 * 9,
= 50 * 3 ,
= 150 meter.
Distance = Speed * Time.
Or lenght = Speed * Time .
=( 60 *5/18) * 9,
= 50/3 * 9,
= 50 * 3 ,
= 150 meter.
Yahya Haider said:
1 decade ago
60 km = 60 x 1000 m = 60000 m.
1 hour = 60 x 60 = 3600 seconds.
So, Length/Distance = Speed x Time.
= 60000 m/3600 s x 9 s.
= 149.999.
= nearly 150m.
Therefore option D is correct answer.
1 hour = 60 x 60 = 3600 seconds.
So, Length/Distance = Speed x Time.
= 60000 m/3600 s x 9 s.
= 149.999.
= nearly 150m.
Therefore option D is correct answer.
Jai said:
3 years ago
from the above statement:
60,000 m is crossed in=>3600 s.
? m is crossed in=> 9 s.
60000/x => 3600/9.
Do a normal cross-division method to find x. That's the answer.
60,000 m is crossed in=>3600 s.
? m is crossed in=> 9 s.
60000/x => 3600/9.
Do a normal cross-division method to find x. That's the answer.
(25)
Gowtham reddy said:
1 decade ago
Length of the train = 9*50/3 = 150.
If train crosses pole in 20 seconds.
Length of the train = 20*50/3?
Is the length of the train depend on the time the it crosses the pole? Please answer.
If train crosses pole in 20 seconds.
Length of the train = 20*50/3?
Is the length of the train depend on the time the it crosses the pole? Please answer.
VIVEK KUMAR said:
8 years ago
Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres. How? explain me with simplification, please.
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