Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
626 comments Page 8 of 63.
Spandana pamuru said:
10 months ago
150 is the answer.
First of all, we convert speed into m/sec because time is in sec, so we can divide.
Speed * 5/18
Then we can calculate using the length formula i.e.., speed * time.
50/3 * 9 = 150m
So, the answer is 150m.
First of all, we convert speed into m/sec because time is in sec, so we can divide.
Speed * 5/18
Then we can calculate using the length formula i.e.., speed * time.
50/3 * 9 = 150m
So, the answer is 150m.
(10)
Jdajose said:
1 decade ago
Why don't we just convert 9 sec into hour? It would be easier to do the v = d/t formula.
9 s (1 min/60 s) (1 hr/60 min) = 0.0025 hr.
Then substitute: 60 km/hr = d/0.0025 hr.
D = 0.15 km/hr (1000 m).
Distance = 150 meters.
9 s (1 min/60 s) (1 hr/60 min) = 0.0025 hr.
Then substitute: 60 km/hr = d/0.0025 hr.
D = 0.15 km/hr (1000 m).
Distance = 150 meters.
Arvind_ap said:
1 decade ago
1 km = 1000 meters.
1 hr = 3600 seconds.
1 km/hr = 1000/3600 m/s.
= 10/36 m/s.
= 5/18 m/s.
1 km/hr = 5/18 m/sec.
60 km/hr = 60 x 5/18 m/sec.
= (60 x 5)/18.
= 300/18.
So in 1 sec speed is 16.66.
9 sec = 16.66*9 = 150.
1 hr = 3600 seconds.
1 km/hr = 1000/3600 m/s.
= 10/36 m/s.
= 5/18 m/s.
1 km/hr = 5/18 m/sec.
60 km/hr = 60 x 5/18 m/sec.
= (60 x 5)/18.
= 300/18.
So in 1 sec speed is 16.66.
9 sec = 16.66*9 = 150.
Akshay Babu said:
2 years ago
Speed = 60 KM/H.
D = ?
T = 9 S.
[Km/h - M/s = 5/18] [M/s - Km/h = 18/5].
Speed is in km/h and time is in seconds.
Convert the speed from km/h to M/s.
So,
Speed = 60 * 5/18 = 50/3 (Fraction).
D = 50/3 * 9 =450/3 = 150 M.
D = ?
T = 9 S.
[Km/h - M/s = 5/18] [M/s - Km/h = 18/5].
Speed is in km/h and time is in seconds.
Convert the speed from km/h to M/s.
So,
Speed = 60 * 5/18 = 50/3 (Fraction).
D = 50/3 * 9 =450/3 = 150 M.
(15)
Satish said:
1 decade ago
Another simple way.
We have to find the length of the train (in mts).
Given in km/Hr ==> 5/18 mts/sec. (1).
Also given time to cross the post i.e. in Sec.
Multiply 1 & sec => (mts/sec) *sec ==mts (ur answer).
We have to find the length of the train (in mts).
Given in km/Hr ==> 5/18 mts/sec. (1).
Also given time to cross the post i.e. in Sec.
Multiply 1 & sec => (mts/sec) *sec ==mts (ur answer).
Aditya said:
1 decade ago
Sonali invests 15% of her monthly salary in insurance policies. She spends 55% of her monthly salary in shopping and on household expenses. She saves the remaining amount of Rs. 12,750. What is Sonali's monthly income?
Litukander said:
9 years ago
Train of length = x.
Speed of train is 60km/hr.
1km is 1000 * 60 =60000.
1hr is 60 minutes * 1hr =3600.
60000 ÷ 3600=16.6667.
Said that 9sec crosses a pole ,then
X = 16.667 * 9sec = 150m.
Distance = speed * time.
Speed of train is 60km/hr.
1km is 1000 * 60 =60000.
1hr is 60 minutes * 1hr =3600.
60000 ÷ 3600=16.6667.
Said that 9sec crosses a pole ,then
X = 16.667 * 9sec = 150m.
Distance = speed * time.
Sushmi said:
1 decade ago
Length of a train = (speed *time).
1 km - 1000 meter.
60 km - ?
60*1000 = 6000 meter = speed.
1 hr - 3600 seconds.
? - 9 second.
3600/9 = time.
So, LENGTH OF TRAIN = 6000*3600/9 = 150 METER.
THIS METHOD VERY EASY.
1 km - 1000 meter.
60 km - ?
60*1000 = 6000 meter = speed.
1 hr - 3600 seconds.
? - 9 second.
3600/9 = time.
So, LENGTH OF TRAIN = 6000*3600/9 = 150 METER.
THIS METHOD VERY EASY.
Petchi Raja said:
3 years ago
@All.
Here, is my expplanation.
The train runs at 60 km/hr which means it will reach 60 km in 60 mins.
therefore 1 km/min = 1000m/60s = 16.66m/1s,
The train crosses 16.66 metres for each second.
So 16.66 * 9 = 150.
Here, is my expplanation.
The train runs at 60 km/hr which means it will reach 60 km in 60 mins.
therefore 1 km/min = 1000m/60s = 16.66m/1s,
The train crosses 16.66 metres for each second.
So 16.66 * 9 = 150.
(186)
RAMAN said:
6 months ago
Here is the answer for 5/18.
Conversion of km/hr to m/s.
Let.
Km = 1000 m.
hr = 3600 sec.
So,
Km/hr = 1000/3600 (m/s),
Both cancell with 200,
So then. 1000/3600 = 5/18.
Because 200 has the greatest common divisor.
Conversion of km/hr to m/s.
Let.
Km = 1000 m.
hr = 3600 sec.
So,
Km/hr = 1000/3600 (m/s),
Both cancell with 200,
So then. 1000/3600 = 5/18.
Because 200 has the greatest common divisor.
(36)
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Length of the train =