Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 6 of 61.
Naldo said:
2 years ago
How do we get 50/3? please explain.
(37)
Anuradha said:
2 years ago
How we get 50/3? Please explain.
(37)
Vamsi said:
2 years ago
Thanks all for explaining the answer.
(37)
Aaftab ali said:
3 years ago
Speed = 60 km/hr
Time = 9
Length = ?
Length = speed * time.
The first step convert km/hr into m/s
Formula is [ km/hr * 5/18 ] = m/s.
So,
60 km/hr * 5/18 = 50/3 m/s.
Now you have speed in metre so find the length now......
Speed * time = length.
50/3 * 9 = ? (Length).
150 = length.
So, the answer is 150 m.
Time = 9
Length = ?
Length = speed * time.
The first step convert km/hr into m/s
Formula is [ km/hr * 5/18 ] = m/s.
So,
60 km/hr * 5/18 = 50/3 m/s.
Now you have speed in metre so find the length now......
Speed * time = length.
50/3 * 9 = ? (Length).
150 = length.
So, the answer is 150 m.
(36)
Vaishnavi said:
1 year ago
60 * 9 = 540,
540 * 5/18 = 150.
540 * 5/18 = 150.
(36)
PRASHANTH said:
12 months ago
I still don't understand. How 5/18 came?
Please explain to me.
Please explain to me.
(35)
Jyothi said:
1 year ago
Conversion formula for km/hr into m/sec = 5/18.
Conversion formula for m/sec into k/m = 18/5.
Conversion formula for m/sec into k/m = 18/5.
(34)
Utkarsh Anand said:
10 months ago
@All.
5/18 was used to convert km/hr into m/sec.
5/18 was used to convert km/hr into m/sec.
(33)
Gurram bhargavi said:
2 years ago
Length of train = speed * time.
= 9 * 60 * 5/18(converting km/hr into m/sec).
= 150 meters.
= 9 * 60 * 5/18(converting km/hr into m/sec).
= 150 meters.
(32)
Divya sash said:
1 month ago
Speed = 60 km/hr = 16.67 m/s.
Distance = Speed × Time = 16.67 × 9 = 150 m.
Distance = Speed × Time = 16.67 × 9 = 150 m.
(31)
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m/sec
Length of the train =