Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
586 comments Page 5 of 59.
Raushan kumar said:
2 years ago
Given, that.
Speed=60 km/hr.
Time=9 sec.
Time is given in sec so we convert the given speed km/hr into sec.
So, 60*5/18 m/sec=50/3 m/sec.
Therefore, the length of the train is =>speed * time.
50/3*9= 150 m/s.
Speed=60 km/hr.
Time=9 sec.
Time is given in sec so we convert the given speed km/hr into sec.
So, 60*5/18 m/sec=50/3 m/sec.
Therefore, the length of the train is =>speed * time.
50/3*9= 150 m/s.
(42)
Edward Casandra oghenekaro said:
1 year ago
Here, how did you get the 50? Anyone, please explain to me.
(42)
Neha kumari said:
11 months ago
For converting km to m 60*1000 = 60000m.
For converting hrs. to sec. 60 * 60 = 3600sec.
60000/3600 = 16.6666.
16.666 * 9 = 150.
For converting hrs. to sec. 60 * 60 = 3600sec.
60000/3600 = 16.6666.
16.666 * 9 = 150.
(42)
Gauri Bhalerao said:
12 months ago
How 5/18 came, can anyone explain me? Please.
(40)
Sneha said:
3 months ago
How did you calculate 5/18? Please explain to me.
(40)
Faheem said:
2 years ago
How did the 5/18 came? Can anyone explain it?
(38)
Saipriya said:
7 months ago
1km = 1000m,
1hr = 3600s.
1km/hr = 1000/3600.
= 5/18 m/s.
1hr = 3600s.
1km/hr = 1000/3600.
= 5/18 m/s.
(38)
Naldo said:
2 years ago
How do we get 50/3? please explain.
(37)
Anuradha said:
2 years ago
How we get 50/3? Please explain.
(37)
Vamsi said:
1 year ago
Thanks all for explaining the answer.
(37)
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