Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 53 of 59.
Saumya tripathi said:
11 months ago
Yes, the answer should be 150.
(9)
Neha kumari said:
11 months ago
For converting km to m 60*1000 = 60000m.
For converting hrs. to sec. 60 * 60 = 3600sec.
60000/3600 = 16.6666.
16.666 * 9 = 150.
For converting hrs. to sec. 60 * 60 = 3600sec.
60000/3600 = 16.6666.
16.666 * 9 = 150.
(42)
SREENIVASULU said:
11 months ago
Given, S = 60 km/hr,
Time(T) = 9 sec and L(T)=?
Speed(S) = (60 * 5/18) = (50/3 m/sec).
L(T) = S * T.
L(T) = (50/3*9)m.
= 150m.
Time(T) = 9 sec and L(T)=?
Speed(S) = (60 * 5/18) = (50/3 m/sec).
L(T) = S * T.
L(T) = (50/3*9)m.
= 150m.
(10)
Benetict said:
11 months ago
60km/60min = 1km/min.
1km = 1000metres , 1hr = 60mins.
1000m/60min = 16.666667.
16.666667 * 9 = 150metres.
1km = 1000metres , 1hr = 60mins.
1000m/60min = 16.666667.
16.666667 * 9 = 150metres.
(79)
Ritik negi said:
11 months ago
1 km = 1000 m,
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
(106)
Ankit kumar said:
10 months ago
60*9/18.
50/3.
50/3*9.
= 150 Ans.
50/3.
50/3*9.
= 150 Ans.
(8)
Ezhil N said:
10 months ago
Conversion formula for km/hr into m/sec = 5/18.
Conversion formula for m/sec into k/m = 18/5.
Conversion formula for m/sec into k/m = 18/5.
(55)
Sree nithi said:
10 months ago
Answer should be 150
(5)
Nithi said:
10 months ago
According to me, the right answer should be 150.
(8)
Karegowda B H said:
9 months ago
60 * 1000m/3600s = 16.66m/s.
So, distance = 16.66 * 9 = 150m.
So, distance = 16.66 * 9 = 150m.
(28)
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