Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 53 of 59.
Rakshith devraj said:
1 decade ago
Guys check this out. !
This comment is to make you understand conversion of km/hr to m/s by using easy method. ,
Observe carefully conversion of km/hr to m/s. ,
12*1=12.
12*2=24.
12*3=36.
12*4=48.
12*5=60.
For any number (which has to be converted to m/s from km/hr) coming as the result (r) of multiplication table of 12. , you can easily write it as (quotient*10) /3 m/s. ,
Example:- 60km/hr = 50/3 m/s.
This comment is to make you understand conversion of km/hr to m/s by using easy method. ,
Observe carefully conversion of km/hr to m/s. ,
12*1=12.
12*2=24.
12*3=36.
12*4=48.
12*5=60.
For any number (which has to be converted to m/s from km/hr) coming as the result (r) of multiplication table of 12. , you can easily write it as (quotient*10) /3 m/s. ,
Example:- 60km/hr = 50/3 m/s.
TALADA SANDEEP said:
1 decade ago
Since time is given in seconds , sure you have to convert velocity of train in units of m/sec
Since 1 km = 1000 m
and 1 hr =60 m = 60*60 sec,
According to question,speed 60 km/hr = 60 * (1000/3600) = 50/3 m/sec, time = 9 sec
We know that , distance=speed*time,
therefore length = (50/3)*9 =150 m.
Since 1 km = 1000 m
and 1 hr =60 m = 60*60 sec,
According to question,speed 60 km/hr = 60 * (1000/3600) = 50/3 m/sec, time = 9 sec
We know that , distance=speed*time,
therefore length = (50/3)*9 =150 m.
Kusuma said:
1 decade ago
In simple way,
time/time = length/length.
Here we convert the 1 hour into seconds and the given time is 9 seconds.
We convert the kilo meters into meters then we can easily solve it.
3600/9 = 6000/x.
X = 150m.
time/time = length/length.
Here we convert the 1 hour into seconds and the given time is 9 seconds.
We convert the kilo meters into meters then we can easily solve it.
3600/9 = 6000/x.
X = 150m.
Sandeep said:
1 decade ago
Firsst 60 km/sec need to be converted in to meter /second.
It could be by multiply by 60*5/18 and then it multiply by 9 secound and hence anse we get 150 meter.
It could be by multiply by 60*5/18 and then it multiply by 9 secound and hence anse we get 150 meter.
Lokesh said:
1 decade ago
Local Train Leaves from a station at an intervals of 15 mins at a speed of 16kmph. A man moving from oppsite direction meets the train at an interval of 12 min. find the speed of that man?
Satish said:
1 decade ago
Another simple way.
We have to find the length of the train (in mts).
Given in km/Hr ==> 5/18 mts/sec. (1).
Also given time to cross the post i.e. in Sec.
Multiply 1 & sec => (mts/sec) *sec ==mts (ur answer).
We have to find the length of the train (in mts).
Given in km/Hr ==> 5/18 mts/sec. (1).
Also given time to cross the post i.e. in Sec.
Multiply 1 & sec => (mts/sec) *sec ==mts (ur answer).
Sudharsan said:
1 decade ago
Let the length of the train be x.
3600/9=6000/x.
X=150m !
3600/9=6000/x.
X=150m !
Hitesh said:
1 decade ago
When I saw the explanation I was confused that why these gyes used 5/18 to multiply But now I got it. Thanks!
Gokul said:
1 decade ago
Really nice explanation.
Shubham said:
1 decade ago
How did you calculate speed ?.
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