Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
613 comments Page 52 of 62.
Elamathi.A said:
1 decade ago
A bus crossing a 42 kilometers in 50 minutes. What is the average speed of the bus?
Nithya said:
1 decade ago
Hi @Latha! Can you explain this problem (sqrt(3N))^3/2 = 90?
Raju said:
1 decade ago
(60*1000*9)m/3600s = 150m.
Ravi1 said:
1 decade ago
Length always in meters so in order to get meters we just multiply it.
Latha said:
1 decade ago
Hi Vishnu.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
Nagesh said:
1 decade ago
Distance = speed*time(50/2*9 = 150)m.
So, 150 m is distance traveled by the train, length of the train can be lower than distance. So can't say 150 m exact.
So, 150 m is distance traveled by the train, length of the train can be lower than distance. So can't say 150 m exact.
Ramesh said:
1 decade ago
3600sec = 60*10^3m.
9sec = ?.
answer = 9*60000/3600 = 150m.
Its very simple,
But I like your methods of solving for answer.
9sec = ?.
answer = 9*60000/3600 = 150m.
Its very simple,
But I like your methods of solving for answer.
Atul said:
1 decade ago
1hr = 60Km.
3600sec = 60000 m.
1sec = 60000/3600 = 50/3.
9 sec = (50/3)*9 = 150m.
3600sec = 60000 m.
1sec = 60000/3600 = 50/3.
9 sec = (50/3)*9 = 150m.
Arun said:
1 decade ago
To remember the formula velocity = d/t (M/s).
d is distance measured in metre(m).
T is the time taken in seconds(s).
So the unit of velocity is (m/s).
d is distance measured in metre(m).
T is the time taken in seconds(s).
So the unit of velocity is (m/s).
Palakananda said:
1 decade ago
Thanks for nice explanation you can solve same as followed.
Total exp = 15%+55% = 70%
Let salary Rs.100
Save = 100-70 = Rs.30%
Rs.30% = 12750.
100% = 12750/30x100 = 42500.
Total exp = 15%+55% = 70%
Let salary Rs.100
Save = 100-70 = Rs.30%
Rs.30% = 12750.
100% = 12750/30x100 = 42500.
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m/sec
Length of the train =