Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
120 metres
180 metres
324 metres
150 metres
Answer: Option
Explanation:

Speed = 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

Length of the train = 50 x 9 m = 150 m.
3

Discussion:
613 comments Page 51 of 62.

Sanket said:   1 decade ago
Give me Different type of Examples on same logical base.

Siri said:   1 decade ago
I too want to know encoding and decoding?

Geetha(VG) said:   1 decade ago
Can you explain the encoding and decoding problems?

Vijay katwal said:   1 decade ago
(60*1000*9)m/3600s = 150m.

Abhi said:   1 decade ago
Can you explain this problem (sqrt(3N))^3/2 = 90?

Raji said:   1 decade ago
I couldn't expect that for a single question which is having so many methods.

Kuldeep said:   1 decade ago
*Simple solution*

We know that,

1) 60km/1hr= 60000m/3600sec , (1hr=3600sec).

*Calulation = 60000/3600 = 16.66m/sec.

16.66x9 = 149.99 = 150m answer.

Pradeep said:   1 decade ago
Distance = speed*time(50/2*9 = 150) m.

So, 150 m is distance traveled by the train, length of the train can be lower than distance. So can't say 150 m exact.

Pradeep said:   1 decade ago
The answer is simple. We are converting the 'kilo-meters/hour' value into 'meters/second'.

Let me explain about converting km/hr into m/s in detail.

1 km = 1000 meters.
1 hr = 3600 seconds.

1 km/hr = 1000/3600 m/s

= 10/36 m/s

= 5/18 m/s.

Therefore 1 km/hr = 5/18 m/sec.

Savitha said:   1 decade ago
Hi please help me to get the answer for (sqrt (3N))^3/2=90..


Post your comments here:

Your comments will be displayed after verification.