Aptitude - Problems on Trains - Discussion

@Udai.

Its very easy to convert m/sec in to km/hour,
Just multiply 18/5.

For example if we want to convert 5meter/sec in to km/sec then we will convert meter into km and sec in to hour.

That is 5meter=(5/1000)km and 1sec=(1/3600)hour.

So 5m/sec={(5/1000)/(1/3600)} km/hour.

or (5*3600)/(1*1000) km/hour

or (5*36)/(10) km /hour

or (5*18)/(5) km/hour

or 5 km/hour.

How to convert feet into meter?

How to convert m/sec in to km/hour?

Total exp= 15%+55%= 70%

Let salary rs.100

Save= 100-70= Rs.30%

Rs.30%= 12750.

100% = 12750/30x100=42500.

Speed convert km/h to m/sec speed=[60*5/18]m/sec
speed=[50/3]m/sec.

Distance=[speed*time]
Length of the train=[50/3*9]
=150m.

Speed = [60*5/18]m/sec=50/3 m/sec.

50/3*9 = 150mtrs.

Similarly,

Speed = [60*5/18]m/sec=50/3 m/sec.

50/3*9 = 150mtrs.

Here, give train travels at a speed of (60*5/18) m/s, that is for one second it travels a distance of 50/3 m/s. So the distance traveled for 9 seconds gives the actual length of train, that is 50/3*9=150m.

We know that
1km=1000meters
1hr=3600seconds
1km/1hr=1000/3600=10/36=5/18m/s
1km/hr=5/18m/s
60km/hr=(60*5/18).

Let length of the train be 'x' metres...
Speed of the train = 60km/hr(given)
Time = 9seconds(given)

Refer the formulas for train problems...

As the time is given in seconds and answers are given in metre(train length) We are in need to convert from km/hr to m/s
km/hr = 1000m/(60min*60sec) = 5/18 m/s

Length of the train(distance covered a post)= speed * time
= (60*(5/18))*9
= (50/3)*9
= 150 m

For the train related formulas,check the READ MORE in Left corner(Important formulas)...