Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
120 metres
180 metres
324 metres
150 metres
Answer: Option
Explanation:

Speed = 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

Length of the train = 50 x 9 m = 150 m.
3

Discussion:
587 comments Page 51 of 59.

Gurram bhargavi said:   1 year ago
Length of train = speed * time.
= 9 * 60 * 5/18(converting km/hr into m/sec).
= 150 meters.
(32)

Owais Khan said:   1 year ago
Given;

60 km = 60 * 1000 = 60,000m
1 Hr = 60 * 60 = 3600 Sec.
Solution:

60,000/3600 * 9 Sec. = 150m.
(190)

Akshaya said:   1 year ago
Speed = (60 x 5/18)m/sec=(50/3)m/sec.
Length of the train = (Speed x Time).
Length of the train = (50/3 x 9)m = 150 m.
(13)

Amar Mali said:   1 year ago
Thanks everyone for explaining the answer.
(18)

Susi said:   1 year ago
Speed 60 km/hr.
Time = 9 sec.

1. Convert speed into m/sec.
ie, Speed/3.6 => 60/3.6=16.67 m/sec.

2. To find the length.
Length L =Speed x time.
ie, L= 16.67 x 9 =150.
So the length of the train is 150 m.
(15)

Sandeep said:   1 year ago
Thanks for explaining the answer.
(3)

Amit keshri said:   1 year ago
Length of train = speed * time.
= 9 * 60 * 5/18(converting km/hr into m/sec).
= 150 meters.
(15)

PrabuS said:   1 year ago
60km/hr = 5/18 * 60 m/s = 50/3 m/s.
50m/s means 50 metres for 3 seconds,
Then for 9 seconds - 150 metres.
(7)

Sukanth said:   1 year ago
Thanks all for giving a clear explanation.
(14)

Aathreyapuram Pootharekulu said:   1 year ago
if the start line and finish line are same then the time it will take to cross the line is equal to (the length of the vehicle/speed of the vehicle) that crossed the line.

The train took 9 seconds to cross the same line. It is travelling at the speed of 60 km/hr.

60 km/hr means "it took an hour to travel 60 kms."
60 km/hr = 60 km/1 hr.
= 60,000 m/60 mins.
= 60,000 m/3600 sec.
= 600 m/36 sec.
= 50 m/3 sec = 50/3 m/s.

Let length be (l)

Time taken = length/Speed.
9 sec = (l)metres/(50/3)m/s.
(l) Metres = 9 sec * (50/3) m/s.
(l) = 450/3 metres.
(l) = 150 metres.

The length of the train is 150 metres.
(124)


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