Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
643 comments Page 46 of 65.
Vikas Prasad said:
1 decade ago
I am not able to solve the problem. Please help me by explaining the simple method.
Pooja said:
1 decade ago
I agree with your comment @Sonali.
Solomon said:
1 decade ago
Can you please go over again.
Dayanand said:
1 decade ago
I agree to given solution.
Shashi kant gupta said:
1 decade ago
1hr = 60min and 1km = 1000m.
Let 1min = 6km.
And 1min = 60sec.
1000/60 = 16.6.
16.6 * 9 = 150m.
This is the answer.
Let 1min = 6km.
And 1min = 60sec.
1000/60 = 16.6.
16.6 * 9 = 150m.
This is the answer.
Lovepreet singh said:
1 decade ago
Well explained @Sundar and @Kalimuthu.
Padmalochan said:
1 decade ago
Why you multiply 5 in 60? How you found 5?
Parth said:
1 decade ago
60min -> 60km.
1min ->1km.
10sec ->166.
So, 9sec -> 149.5.
1min ->1km.
10sec ->166.
So, 9sec -> 149.5.
Sathya said:
1 decade ago
10/36 = 5/18.
If both numerator and denominator can divide by a Single number, then you can divide it.
Here in above problem 10 and 36 both are dividing by 2, that's why the answer is 5/18.
If both numerator and denominator can divide by a Single number, then you can divide it.
Here in above problem 10 and 36 both are dividing by 2, that's why the answer is 5/18.
Sagar said:
1 decade ago
1 Hour = 60 Min.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
1 Min = 60 Sec.
(Min * Sec = 60 * 60 = 3600).
3600 Sec= 60KM.
9 Sec = ?
60 * 9/3600= 0.15.
So, As per the Option Length is 150 MTR.
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m/sec
Length of the train =