Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
643 comments Page 45 of 65.
Gnanavel said:
1 decade ago
If they asking to find the length of the pole, then how to solve it?
Vikas prasad said:
1 decade ago
I can't solve the problem and also can't read it properly what can I do?
I.mahindra reddy said:
1 decade ago
Nice and clear explanations. Thank you all.
Srinivasan said:
1 decade ago
60000m = 6km.
DIVAKAR M S said:
1 decade ago
Good explanation, I understood. Thank you all.
Srinivas said:
1 decade ago
Yeah@ obviously. Mr. Sundar your answer was right but I think your solution is complicated. I need as simple as possible. Will you provide?
Sonali said:
1 decade ago
@Latha, Please explain the solution.
(sqrt(3N))^3/2 = 90.
N = 10.
(sqrt(3N))^3/2 = 90.
N = 10.
Ihhhh said:
1 decade ago
I can't understand. Please help me.
Sonali said:
1 decade ago
Hey, guise your answer is really good. But I have 1 prob how to convert km/hr 1000/3600. In that form 5/18.
But thanks to Arvind. I understand. How to convert. Really thanks again Arvind.
But thanks to Arvind. I understand. How to convert. Really thanks again Arvind.
Marylyn Kaka said:
1 decade ago
Speed = distance(length of train) / Time.
Length of train = speed * time.
First, express 9 seconds in hours since speed is in hours.
9 / 3600 = 0.0025.
Length = speed * time.
= 60 * 0.0025.
= 0.15 km.
Convert 0.15 km to meters since options are in meters.
=0.15 * 1000.
=150 m.
Length of train = speed * time.
First, express 9 seconds in hours since speed is in hours.
9 / 3600 = 0.0025.
Length = speed * time.
= 60 * 0.0025.
= 0.15 km.
Convert 0.15 km to meters since options are in meters.
=0.15 * 1000.
=150 m.
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m/sec
Length of the train =