Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 47 of 59.
Shubhankar said:
8 years ago
Nice explanation. Thank you all.
Gopi said:
8 years ago
Distance = Time *speed.
1km =1000Meteres,
1hr =3600 seconds,
Distance = 60*9/3600 =9/60 km,
Distane in Metres =(9/60)*1000 =150M.
1km =1000Meteres,
1hr =3600 seconds,
Distance = 60*9/3600 =9/60 km,
Distane in Metres =(9/60)*1000 =150M.
Priyanka said:
8 years ago
Very useful explanation. Thanks.
Subashini said:
8 years ago
1 km=3000m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.
Devkar Sunil said:
8 years ago
1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.
9sec=?.
Cross multipication =150m.
Sowmiya said:
8 years ago
Nice explanation, I understand your solution Thanks @Sundar.
Irine said:
8 years ago
I have one doubt.
Why don't you change 9sec into hours and then calculate distance?
Why don't you change 9sec into hours and then calculate distance?
Prasad said:
8 years ago
s=60*5/18,t=9;
s=d/t;
d=s*t=60*5/18*9=150;
s=d/t;
d=s*t=60*5/18*9=150;
Santhosh said:
8 years ago
Nice explanation. Thanks.
Dileepkumar said:
8 years ago
Nice explanation.
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