Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 35 of 59.
Swamy chukkala said:
10 years ago
Well,
In my view 36 sec ---- 600 mt.
So, 9 sec ----150 mt.
In my view 36 sec ---- 600 mt.
So, 9 sec ----150 mt.
Meenakshi said:
10 years ago
Thanks for all of you for the kind explanation it's very easy to understand.
ANNAMALAI said:
10 years ago
1 km = 1000 m.
60 km = 60000 m.
1 hr = 3600 sec.
= (60000/3600)*9 = 150m.
60 km = 60000 m.
1 hr = 3600 sec.
= (60000/3600)*9 = 150m.
Sudheer said:
10 years ago
How it come 50/3 m/sec? Can you tel me please?
Umesh said:
10 years ago
I just want to check how this module? That's way I comment here.
Sugandhi said:
10 years ago
Thanks, good details of question is well said.
SAI MOHAN REDDY said:
10 years ago
In the above question we can change minutes for seconds.
60*5/18 = (50/3) m/sec.
Length of the train is = (Speed*Time) = 50/3*9 = 150 m.
60*5/18 = (50/3) m/sec.
Length of the train is = (Speed*Time) = 50/3*9 = 150 m.
Mandla kavitha said:
10 years ago
The speed of train is 60 km/h. Time taken by train is 9 sec.
Then length of train is (d = velocity*time).
(60*5)/18*9 =150 m.
Therefore;the length of train is 150 m.
Then length of train is (d = velocity*time).
(60*5)/18*9 =150 m.
Therefore;the length of train is 150 m.
Venkat Reddy said:
10 years ago
Good @Sai Mohan Reddy.
We can also show like this; for 3 sec_____50 mtr, then 9 sec____? mtr;
50*9/3 = 450/3 or (50*3) = 150 mtr length of the train.
(It is a time saving problem, calculation should take place in seconds. 60 kmph means 60000/3600 (m/sec) = 50 mtr in 3 sec. Then calculate for 9 sec).
We can also show like this; for 3 sec_____50 mtr, then 9 sec____? mtr;
50*9/3 = 450/3 or (50*3) = 150 mtr length of the train.
(It is a time saving problem, calculation should take place in seconds. 60 kmph means 60000/3600 (m/sec) = 50 mtr in 3 sec. Then calculate for 9 sec).
Rashmi said:
10 years ago
Thank you sir. Nice explanation.
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