Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 34 of 59.
KEITH said:
1 decade ago
So when the questions says find the length of the train, in such case we have to find the distance i.e. by using the distance formula.
D=S*T.
S=D/T.
T=D/S.
D=S*T.
S=D/T.
T=D/S.
Sachin said:
1 decade ago
This math is simple. But your explanation makes the math more easy to learn specially for beginner like me. Thanks a lot.
Jaibheem said:
1 decade ago
Sir nice explanation thank you so much.
Komala R said:
1 decade ago
Yes nice thank you so much.
Priyesh said:
1 decade ago
60*(5/18)*9 = 150 m.
Yahya Haider said:
1 decade ago
60 km = 60 x 1000 m = 60000 m.
1 hour = 60 x 60 = 3600 seconds.
So, Length/Distance = Speed x Time.
= 60000 m/3600 s x 9 s.
= 149.999.
= nearly 150m.
Therefore option D is correct answer.
1 hour = 60 x 60 = 3600 seconds.
So, Length/Distance = Speed x Time.
= 60000 m/3600 s x 9 s.
= 149.999.
= nearly 150m.
Therefore option D is correct answer.
Farhat said:
1 decade ago
Speed = 60 km/hr.
Time = 9 sec.
Distance = ?
Then, 1 km = 1000 m.
1 hr = 3600 sec.
Because we are to find the distance in metre/sec.
60000*9/3600 = 15 m.
Time = 9 sec.
Distance = ?
Then, 1 km = 1000 m.
1 hr = 3600 sec.
Because we are to find the distance in metre/sec.
60000*9/3600 = 15 m.
Sushmitha said:
1 decade ago
Great explanations.
Ghule santosh said:
1 decade ago
Always train high speed that means m/s.
Jdajose said:
10 years ago
Why don't we just convert 9 sec into hour? It would be easier to do the v = d/t formula.
9 s (1 min/60 s) (1 hr/60 min) = 0.0025 hr.
Then substitute: 60 km/hr = d/0.0025 hr.
D = 0.15 km/hr (1000 m).
Distance = 150 meters.
9 s (1 min/60 s) (1 hr/60 min) = 0.0025 hr.
Then substitute: 60 km/hr = d/0.0025 hr.
D = 0.15 km/hr (1000 m).
Distance = 150 meters.
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