Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 36 of 59.
Priyanka padhi said:
10 years ago
Thanks @Sundar. That's was a very nice explanation. For those who are not strong in this section, this is the best way to make them easily understandable.
Roko Meena said:
10 years ago
By using unit logic we can solve this question easily in question (given unit are km, m, sec).
Length of train in meter.
So, 60 km/hr.
= 60*1000 m/1*3600 sec.
1 km = 1000 m and 1 hour = 3600 sec.
= 1000 m*9 sec/3600 sec.
Sec unit cancel so I find (meter) 150 m.
Length of train in meter.
So, 60 km/hr.
= 60*1000 m/1*3600 sec.
1 km = 1000 m and 1 hour = 3600 sec.
= 1000 m*9 sec/3600 sec.
Sec unit cancel so I find (meter) 150 m.
Ghore said:
10 years ago
Very good explanation.
Suganthi said:
10 years ago
Hey really all are explanation is super. So thank you for all.
Divya said:
10 years ago
Difference between kmph/mps?
Selva said:
10 years ago
How will you find the length of that pole?
Sachinkumar said:
10 years ago
Thank you, you explained this question in a simple way I'm which we can understand easily.
Omkar said:
10 years ago
Does the formula of the length of the train is (Speed*Time)?
Sajan said:
10 years ago
= 9/3600*60*1000.
= 9 seconds/3600 seconds (We convert hours to seconds).
= 60*1000 (Convert KM to M).
= 9/3600*60000 = 150 M.
= 9 seconds/3600 seconds (We convert hours to seconds).
= 60*1000 (Convert KM to M).
= 9/3600*60000 = 150 M.
Chandu said:
10 years ago
1 sec = 5/8 m.
36 sec = 5/18*36 = 10 m.
36 sec = 5/18*36 = 10 m.
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