Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
584 comments Page 3 of 59.
Biranu medeksa said:
5 months ago
How 5/18 came? Anyone, please explain to me.
(26)
G david said:
5 months ago
Nice question. Thanks.
(3)
ABISHEK said:
5 months ago
150m is the correct answer.
(6)
Dadasaheb kamble said:
5 months ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
(118)
Akhil Joseph K J said:
6 months ago
Calculation: 60× (5 / 18)
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
(9)
Md shahid said:
6 months ago
The answer is 150m.
(6)
Kusuma Kumari Neelam said:
6 months ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2*5 = 10 and 2*18=36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2*5 = 10 and 2*18=36).
(24)
Vuruturu Jyothi sankar said:
6 months ago
Speed = 60 km/h = 60 * 5/18
= 50/3 m/s.
Time taken = 9 sec.
Length = speed * time = 50/3 * 9.
=150 m.
= 50/3 m/s.
Time taken = 9 sec.
Length = speed * time = 50/3 * 9.
=150 m.
(1)
Kaustubh Kishor Salunkhe said:
6 months ago
@All Everyone,
For the people who asking how 5/18 came?
It is used to convert KMPH to MPS
Let me explain how and when to use it. The hint is in the Answers we can see 60 km/hr and answers in Meters.
If it's Vise Versa we will use 18/5 to get the answer in Kmph.
For the people who asking how 5/18 came?
It is used to convert KMPH to MPS
Let me explain how and when to use it. The hint is in the Answers we can see 60 km/hr and answers in Meters.
If it's Vise Versa we will use 18/5 to get the answer in Kmph.
(6)
Henry Pautu said:
6 months ago
To find the length of the train, we use the formula is Distance=Speed×Time.
Given:
Speed of the train = 60 km/hr.
Time taken to cross the pole = 9 seconds.
Since 1 km/hr = (5/18) m/s, we convert:
60 X 5 / 18 = 300 / 18 = 16.67 m/s.
Since the train crosses a pole (which means the length of the train itself is covered in the given time):
Length of train = 16.67 × 9 = 150 meters.
Given:
Speed of the train = 60 km/hr.
Time taken to cross the pole = 9 seconds.
Since 1 km/hr = (5/18) m/s, we convert:
60 X 5 / 18 = 300 / 18 = 16.67 m/s.
Since the train crosses a pole (which means the length of the train itself is covered in the given time):
Length of train = 16.67 × 9 = 150 meters.
(13)
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