Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
597 comments Page 4 of 60.
Tapentadol said:
8 months ago
60km = 60000m.
1hr = 3600sec.
Now, if 60000m = 3600sec,
x = 9sec.
x = 60000m * 9sec/3600sec.
x = 150m.
1hr = 3600sec.
Now, if 60000m = 3600sec,
x = 9sec.
x = 60000m * 9sec/3600sec.
x = 150m.
(148)
Utkarsh Anand said:
8 months ago
@All.
5/18 was used to convert km/hr into m/sec.
5/18 was used to convert km/hr into m/sec.
(33)
SRIRAM said:
9 months ago
Why we are calculating 5/18 not 18/5? Please explain it.
(23)
Biranu medeksa said:
9 months ago
How 5/18 came? Anyone, please explain to me.
(26)
G david said:
9 months ago
Nice question. Thanks.
(3)
ABISHEK said:
9 months ago
150m is the correct answer.
(6)
Dadasaheb kamble said:
9 months ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2 * 5 = 10 and 2 * 18 = 36).
(119)
Akhil Joseph K J said:
9 months ago
Calculation: 60× (5 / 18)
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
Simplify:
(60×5)/18
Cancel common factors:
60 and 18 have a common factor of 6:
(10×6)×5/(3×6)
Cancel 6:
(10×5)/3 = 50/3.
(9)
Md shahid said:
9 months ago
The answer is 150m.
(6)
Kusuma Kumari Neelam said:
9 months ago
How 5/18 came I will explain.
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2*5 = 10 and 2*18=36).
1 km = 1000 m.
1hr = 60min.
1 min = 60sec.
60min = 3600 sec.
1000/3600 = 5/18.
(Cancelling two zeroes up and down and 2*5 = 10 and 2*18=36).
(24)
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