Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
597 comments Page 29 of 60.
Pavitra said:
3 years ago
1m = 1/1000km and
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
(30)
Srikanth said:
1 decade ago
Can you explain the problem with diagrammatic representation ?
Suganthi said:
1 decade ago
Hey really all are explanation is super. So thank you for all.
Subashini said:
8 years ago
1 km=3000m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.
Ivan said:
11 months ago
I still don't understand. How 5/18 came? Please explain to me.
(20)
Vishnu said:
1 decade ago
Do any one know the relationship betwen miles and kilometers?
Amudeeswari said:
4 years ago
Thanks for all your answers. It helps me a lot to understand.
Kamala said:
2 years ago
Length = speed * time,
L=60 * 5/18,
= 50/3 * 9,
= 150 meters.
L=60 * 5/18,
= 50/3 * 9,
= 150 meters.
(15)
Karegowda B H said:
1 year ago
60 * 1000m/3600s = 16.66m/s.
So, distance = 16.66 * 9 = 150m.
So, distance = 16.66 * 9 = 150m.
(28)
Nithya said:
1 decade ago
Hi @Latha! Can you explain this problem (sqrt(3N))^3/2 = 90?
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m/sec
Length of the train =