Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 29 of 61.
Umesh said:
1 decade ago
I just want to check how this module? That's way I comment here.
Shri said:
10 years ago
@Kalimuthu.
Short, simple and logically understandable answer .
Short, simple and logically understandable answer .
Muhammed Jamsheer said:
2 years ago
@Raj
To convert km to metre;
Km - m = × 5/18.
m - km = × 18/5.
To convert km to metre;
Km - m = × 5/18.
m - km = × 18/5.
(20)
Suriya said:
1 year ago
@Revanth.
We need to cover kmph to mtps 5/18 mtps to kmph 18/5.
We need to cover kmph to mtps 5/18 mtps to kmph 18/5.
(4)
PRASHANTH said:
12 months ago
I still don't understand. How 5/18 came?
Please explain to me.
Please explain to me.
(35)
Pavitra said:
3 years ago
1m = 1/1000km and
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
(30)
Srikanth said:
1 decade ago
Can you explain the problem with diagrammatic representation ?
Suganthi said:
1 decade ago
Hey really all are explanation is super. So thank you for all.
Subashini said:
8 years ago
1 km=3000m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.
60 km=60000.
1 hr=3600sec,
=(60000/3600)*9,
=150m.
Ivan said:
1 year ago
I still don't understand. How 5/18 came? Please explain to me.
(20)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers