Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 28 of 59.
Hanumantha reddy said:
1 decade ago
Hi good morning this problem am not understand please explain me.
Bangaru said:
1 decade ago
@Divya.
Can you explain the problem which was mentioned by you ?
Can you explain the problem which was mentioned by you ?
Kishan said:
1 decade ago
Similarly,
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Umesh said:
10 years ago
I just want to check how this module? That's way I comment here.
Shri said:
9 years ago
@Kalimuthu.
Short, simple and logically understandable answer .
Short, simple and logically understandable answer .
Muhammed Jamsheer said:
2 years ago
@Raj
To convert km to metre;
Km - m = × 5/18.
m - km = × 18/5.
To convert km to metre;
Km - m = × 5/18.
m - km = × 18/5.
(20)
Suriya said:
7 months ago
@Revanth.
We need to cover kmph to mtps 5/18 mtps to kmph 18/5.
We need to cover kmph to mtps 5/18 mtps to kmph 18/5.
(4)
PRASHANTH said:
7 months ago
I still don't understand. How 5/18 came?
Please explain to me.
Please explain to me.
(35)
Pavitra said:
2 years ago
1m = 1/1000km and
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
1s=1/3600hr.
So 1m/s = 3600/1000 = 18/5km/h.
(30)
Srikanth said:
1 decade ago
Can you explain the problem with diagrammatic representation ?
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