Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
597 comments Page 28 of 60.
Anu said:
1 decade ago
Why is the length of train calculated with the formula speed*time?
Sonali said:
9 years ago
@Latha, Please explain the solution.
(sqrt(3N))^3/2 = 90.
N = 10.
(sqrt(3N))^3/2 = 90.
N = 10.
Hanumantha reddy said:
1 decade ago
Hi good morning this problem am not understand please explain me.
Bangaru said:
1 decade ago
@Divya.
Can you explain the problem which was mentioned by you ?
Can you explain the problem which was mentioned by you ?
Kishan said:
1 decade ago
Similarly,
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Umesh said:
1 decade ago
I just want to check how this module? That's way I comment here.
Shri said:
9 years ago
@Kalimuthu.
Short, simple and logically understandable answer .
Short, simple and logically understandable answer .
Muhammed Jamsheer said:
2 years ago
@Raj
To convert km to metre;
Km - m = × 5/18.
m - km = × 18/5.
To convert km to metre;
Km - m = × 5/18.
m - km = × 18/5.
(20)
Suriya said:
10 months ago
@Revanth.
We need to cover kmph to mtps 5/18 mtps to kmph 18/5.
We need to cover kmph to mtps 5/18 mtps to kmph 18/5.
(4)
PRASHANTH said:
10 months ago
I still don't understand. How 5/18 came?
Please explain to me.
Please explain to me.
(35)
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