Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 28 of 61.
Akshata said:
1 year ago
60 * 5/18 = 50/3,
Length = speed * time.
l = 50/3 * 9sec= 150 meters.
Length = speed * time.
l = 50/3 * 9sec= 150 meters.
(5)
Tripta said:
10 years ago
1 km = 1000.
1 hr = 3600 s.
Why it is changed into 10/36 and 5/18?
1 hr = 3600 s.
Why it is changed into 10/36 and 5/18?
Gnanavel said:
9 years ago
If they asking to find the length of the pole, then how to solve it?
Abhishek said:
2 years ago
60 km/h.
1 km/minutes.
1000/60 = 16.6666/sec
16.6666*9 = 150meter.
1 km/minutes.
1000/60 = 16.6666/sec
16.6666*9 = 150meter.
(77)
Giri said:
1 decade ago
1 km = 1000 meters.
1 hr = 3600 seconds.
1 km/hr = 1000/3600 m/s.
1 hr = 3600 seconds.
1 km/hr = 1000/3600 m/s.
Anu said:
1 decade ago
Why is the length of train calculated with the formula speed*time?
Sonali said:
9 years ago
@Latha, Please explain the solution.
(sqrt(3N))^3/2 = 90.
N = 10.
(sqrt(3N))^3/2 = 90.
N = 10.
Hanumantha reddy said:
1 decade ago
Hi good morning this problem am not understand please explain me.
Bangaru said:
1 decade ago
@Divya.
Can you explain the problem which was mentioned by you ?
Can you explain the problem which was mentioned by you ?
Kishan said:
1 decade ago
Similarly,
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers