Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
644 comments Page 27 of 65.
Shyam Prasanth said:
4 years ago
= 60×5/18.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
(12)
Divya sash said:
10 months ago
Speed = 60 km/hr = 16.67 m/s.
Distance = Speed × Time = 16.67 × 9 = 150 m.
Distance = Speed × Time = 16.67 × 9 = 150 m.
(45)
Grace said:
1 decade ago
60000 = 3600.
x = 9.
Cross multiply.
= 3600 x/60000*9.
Answer is 150.
x = 9.
Cross multiply.
= 3600 x/60000*9.
Answer is 150.
Shoaib soudagar said:
9 years ago
You can simply solve like this.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
Arun s said:
4 years ago
1 km = 1000 m,
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
(94)
Ritik negi said:
2 years ago
1 km = 1000 m,
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
(106)
Sada said:
1 decade ago
@Muhammad.
This explanation is good and useful for beginners. Thankyou.
This explanation is good and useful for beginners. Thankyou.
Vikas prasad said:
1 decade ago
I can't solve the problem and also can't read it properly what can I do?
Asfu said:
3 years ago
Still, I am not getting this. Anyone, help me to understand the concept?
(15)
Naresh Thummala said:
1 decade ago
Distance = Speed x time.
Length = (60 x 5/18) x 9.
= 150 MTRS.
Length = (60 x 5/18) x 9.
= 150 MTRS.
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Length of the train =