Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 22 of 61.
Kishan bhanja said:
1 year ago
Speed = 60 km/h = 60 * 5/18 = 50/3 m/s.
Time taken = 9 sec.
Length = speed * time = 50/3 * 9 =150 m.
Time taken = 9 sec.
Length = speed * time = 50/3 * 9 =150 m.
(5)
Bala bhaskar said:
2 years ago
Is the length of the train= distance cover by the train?
Please, anyone help me I have this doubt.
Please, anyone help me I have this doubt.
(4)
Sundar said:
2 decades ago
Feet to Meter conversion: 1 feet = 0.3048 meter
Meter to Feet conversion: 1 meter = 3.28083 feet
Meter to Feet conversion: 1 meter = 3.28083 feet
(2)
Priya said:
1 decade ago
All the explanations are very easy understand and it is more useful for beginners hopeful thanks.
Teja said:
9 years ago
@Sundar, @Kalimuthu & @Sungathan.
Really great explanation. Thank you all for your explanations.
Really great explanation. Thank you all for your explanations.
Darshan thakur said:
1 decade ago
60 km/3600 sec = 0.016667.
0.016667 km/sec*9 sec = 0.15 sec.
0.15 sec*1000 meter = 150 meter.
0.016667 km/sec*9 sec = 0.15 sec.
0.15 sec*1000 meter = 150 meter.
Thangaraj K. said:
1 decade ago
Answer = sec/speed*1000 (i.e. - multiplied with 1000 to convert to metres )
=9/60*1000 = 150m
=9/60*1000 = 150m
Jyothi said:
1 year ago
Conversion formula for km/hr into m/sec = 5/18.
Conversion formula for m/sec into k/m = 18/5.
Conversion formula for m/sec into k/m = 18/5.
(34)
Naveen said:
1 decade ago
Time = Distance/Speed.
From this Distance = Time*Speed.
= 9*(60*(5/18)) = 149.9999.
= 150.
From this Distance = Time*Speed.
= 9*(60*(5/18)) = 149.9999.
= 150.
Dharanish said:
6 years ago
Convert km to m - 60000.
Convert hr to sec - 3600.
60000/3600 = 16.666(speed)*9 (time) = 150.
Convert hr to sec - 3600.
60000/3600 = 16.666(speed)*9 (time) = 150.
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m/sec
Length of the train =