Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 19 of 59.
SAI MOHAN REDDY said:
10 years ago
In the above question we can change minutes for seconds.
60*5/18 = (50/3) m/sec.
Length of the train is = (Speed*Time) = 50/3*9 = 150 m.
60*5/18 = (50/3) m/sec.
Length of the train is = (Speed*Time) = 50/3*9 = 150 m.
Sugandhi said:
10 years ago
Thanks, good details of question is well said.
Mandla kavitha said:
10 years ago
The speed of train is 60 km/h. Time taken by train is 9 sec.
Then length of train is (d = velocity*time).
(60*5)/18*9 =150 m.
Therefore;the length of train is 150 m.
Then length of train is (d = velocity*time).
(60*5)/18*9 =150 m.
Therefore;the length of train is 150 m.
Venkat Reddy said:
10 years ago
Good @Sai Mohan Reddy.
We can also show like this; for 3 sec_____50 mtr, then 9 sec____? mtr;
50*9/3 = 450/3 or (50*3) = 150 mtr length of the train.
(It is a time saving problem, calculation should take place in seconds. 60 kmph means 60000/3600 (m/sec) = 50 mtr in 3 sec. Then calculate for 9 sec).
We can also show like this; for 3 sec_____50 mtr, then 9 sec____? mtr;
50*9/3 = 450/3 or (50*3) = 150 mtr length of the train.
(It is a time saving problem, calculation should take place in seconds. 60 kmph means 60000/3600 (m/sec) = 50 mtr in 3 sec. Then calculate for 9 sec).
Priyanka padhi said:
10 years ago
Thanks @Sundar. That's was a very nice explanation. For those who are not strong in this section, this is the best way to make them easily understandable.
Rashmi said:
10 years ago
Thank you sir. Nice explanation.
Ghore said:
10 years ago
Very good explanation.
Roko Meena said:
10 years ago
By using unit logic we can solve this question easily in question (given unit are km, m, sec).
Length of train in meter.
So, 60 km/hr.
= 60*1000 m/1*3600 sec.
1 km = 1000 m and 1 hour = 3600 sec.
= 1000 m*9 sec/3600 sec.
Sec unit cancel so I find (meter) 150 m.
Length of train in meter.
So, 60 km/hr.
= 60*1000 m/1*3600 sec.
1 km = 1000 m and 1 hour = 3600 sec.
= 1000 m*9 sec/3600 sec.
Sec unit cancel so I find (meter) 150 m.
Divya said:
10 years ago
Difference between kmph/mps?
Selva said:
10 years ago
How will you find the length of that pole?
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