Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 20 of 59.
Suganthi said:
10 years ago
Hey really all are explanation is super. So thank you for all.
Sachinkumar said:
10 years ago
Thank you, you explained this question in a simple way I'm which we can understand easily.
Omkar said:
10 years ago
Does the formula of the length of the train is (Speed*Time)?
Sajan said:
10 years ago
= 9/3600*60*1000.
= 9 seconds/3600 seconds (We convert hours to seconds).
= 60*1000 (Convert KM to M).
= 9/3600*60000 = 150 M.
= 9 seconds/3600 seconds (We convert hours to seconds).
= 60*1000 (Convert KM to M).
= 9/3600*60000 = 150 M.
Chandu said:
10 years ago
1 sec = 5/8 m.
36 sec = 5/18*36 = 10 m.
36 sec = 5/18*36 = 10 m.
Sam said:
10 years ago
1000/60 = 16.666.
= 16.666x9 = 150.
One more 1000/10 = 100.
= 60/10 = 6.
= 100 mtr/6 sec.
= 50 mtr/3 sec.
So 150 mtr in 9 sec.
= 16.666x9 = 150.
One more 1000/10 = 100.
= 60/10 = 6.
= 100 mtr/6 sec.
= 50 mtr/3 sec.
So 150 mtr in 9 sec.
Naveen said:
10 years ago
Time = Distance/Speed.
From this Distance = Time*Speed.
= 9*(60*(5/18)) = 149.9999.
= 150.
From this Distance = Time*Speed.
= 9*(60*(5/18)) = 149.9999.
= 150.
Bulu said:
10 years ago
How 1 hr can be written as 5/3 km/hr?
Tripta said:
10 years ago
1 km = 1000.
1 hr = 3600 s.
Why it is changed into 10/36 and 5/18?
1 hr = 3600 s.
Why it is changed into 10/36 and 5/18?
R SUBRAMANI said:
9 years ago
Easy to improve our knowledge.
1 hour = 3600 secs.
1 km = 1000 m.
3600/1000 = 36/10 = 5/18.
60*5/18*9 = 150 m.
1 hour = 3600 secs.
1 km = 1000 m.
3600/1000 = 36/10 = 5/18.
60*5/18*9 = 150 m.
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